3 years ago

Global climate could be greatly altered if the earth's energy budget were out of balance.

Physics

2 answers:

Pie3 years ago

7 0

True. Hope it helped!

Iteru [2.4K]3 years ago

5 0

The answer is True That's it...

You might be interested in

HEY CAN ANYONE PLS PLS PLS HELP ME OUT IN DIS I AM STRUGGLING TOO MUCH

meriva

<h3>Answer: 104.5 cubic cm</h3>

=======================================================

Work Shown:

r = radius = 1.045 cm

h = height = 30.48 cm

pi = 3.141 approximately

V = volume of cylinder

V = pi*r^2*h

V = 3.141*(1.045)^2*30.48

V = 104.547940002

V = 104.5 cubic cm

6 0

3 years ago

Pleasse help

GaryK [48]

Hi,

The correct answer is letter B.

The last group contains noble gases, while both along the top and along the bottom the elements on the right are non-metals.

3 0

3 years ago

Read 2 more answers

One possible explanation for a galaxy's type invokes the angular momentum of the protogalactic cloud from which it formed. Suppo

garik1379 [7]

Answer:

A spiral galaxy

Explanation:

6 0

3 years ago

The distribution of total body protein in healthy adult men is approximately Normal, with mean 12.3 kg and standard deviation 0.

Sophie [7]

Answer:

$P(12.25\leq x \leq 12.35 ) = 0.9876$

Explanation:

given,

mean (μ) = 12.3 Kg

standard deviation (σ ) = 0.1

random sample = 25

probability between 12.25 and 12.35 kg

$P(12.25\leq x \leq 12.35 ) = P(\dfrac{12.35-12.3}{\dfrac{0.1}{\sqrt{n}}}\leq z)- P(\dfrac{12.25-12.3}{\dfrac{0.1}{\sqrt{n}}}\leq z)$

$P(12.25\leq x \leq 12.35 ) = P(\dfrac{12.35-12.3}{\dfrac{0.1}{\sqrt{25}}}\leq z)- P(\dfrac{12.25-12.3}{\dfrac{0.1}{\sqrt{25}}}\leq z)$

$P(12.25\leq x \leq 12.35 ) = P(\dfrac{12.35-12.3}{\dfrac{0.1}{5}}\leq z)- P(\dfrac{12.25-12.3}{\dfrac{0.1}{5}}\leq z)$

$P(12.25\leq x \leq 12.35 ) = P(\dfrac{5 (12.35-12.3)}{0.1}\leq z)- P(\dfrac{5(12.25-12.3)}{0.1}\leq z)$

$P(12.25\leq x \leq 12.35 ) = P(\dfrac{2.5\leq z)- P(-2.5\leq z)$

using z-table

$P(12.25\leq x \leq 12.35 ) = 0.9938 - 0.0062$

$P(12.25\leq x \leq 12.35 ) = 0.9876$

4 0

3 years ago

Заряди +10 нКл і +18нКл розташовані на відстані 12 см один від одного.Яка сила діятиме на заряд +2 нКл,який розміщений на прямій

ludmilkaskok [199]

Hdjdjdjdhfhdbdhdbdbdhdhdhdhdhdhdgdgdhd

3 0

3 years ago