A 50-kg box is being pushed along a horizontal surface. The coefficient of static friction between the box and the ground is 0.6
1 answer:
To solve the exercise it is necessary to apply the concepts related to Newton's Second Law, as well as the definition of Weight and Friction Force.
According to the problem there is a movement in the body and it is necessary to make a sum of forces on it, so that
There are two forces acting on the body, the Force that is pushing and the opposing force that is that of friction, that is
To find the required force then,
By definition we know that the friction force is equal to the multiplication between the friction coefficient and the weight, that is to say
Therefore the horizontal force applied on the block is B) 230N
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examples is that in the steel when you heat a steel the particles inside it will vibrate then the particles speed up because the vibration increases, therefore the temperature increases so a a thermal expansion occurs that the vibration of the particles will take up more space so the steel bar expands slightly in all Direction if the temperature Falls the reverse happens and the material or steel contracts which means get smaller .
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