Based on the information you provided, this means the wave is traveling 50 meters every ten seconds. Meaning it is traveling 50/10 meters per second.
When you simplify you get 5 meters per second.
Answer:
The spring constant of the spring is 47.62 N/m
Explanation:
Given that,
Mass that is attached with the spring, m = 29 g = 0.029 kg
The spring makes 20 complete vibrations in 3.1 s. We need to find the spring constant of the spring. We know that the number of oscillations per unit time is called frequency of an object. So,

f = 6.45 Hz
The frequency of oscillator is given by :

k is the spring constant


k = 47.62 N/m
So, the spring constant of the spring is 47.62 N/m. Hence, this is the required solution.
Answer:
m = 27752.7 [kg]
Explanation:
To solve this problem we must first use the following equation of kinematics.

where:
Vf = final velocity = 240 [km/h]
Vo = initial velocity = 0
a = acceleration [m/s²]
t = time = 2 [s]
But first we must convert the speed from kilometers per hour to meters per second.
![240[\frac{km}{h} ]*(\frac{1h}{3600s} )*(\frac{1000m}{1km} )=66.67[m/s]](https://tex.z-dn.net/?f=240%5B%5Cfrac%7Bkm%7D%7Bh%7D%20%5D%2A%28%5Cfrac%7B1h%7D%7B3600s%7D%20%29%2A%28%5Cfrac%7B1000m%7D%7B1km%7D%20%29%3D66.67%5Bm%2Fs%5D)
Now replacing:
![66.67 = 0 +a*2\\a = 33.33 [m/s^{2} ]](https://tex.z-dn.net/?f=66.67%20%3D%200%20%2Ba%2A2%5C%5Ca%20%3D%2033.33%20%5Bm%2Fs%5E%7B2%7D%20%5D)
Now using Newton's second law which is defined as the product of mass by acceleration we can determine the mass of the jet.
∑F = m*a
![925000=m*33.33\\m = 925000/33.33\\m = 27752.7 [kg]](https://tex.z-dn.net/?f=925000%3Dm%2A33.33%5C%5Cm%20%3D%20925000%2F33.33%5C%5Cm%20%3D%2027752.7%20%5Bkg%5D)
Answer:
Because of the presence of air resistance
Explanation:
When an object is in free fall, ideally there is only one force acting on it:
- The force of gravity, W = mg, that pushes the object downward (m= mass of the object, g = acceleration of gravity)
However, this is true only in absence of air (so, in a vacuum). When air is present, it exerts a frictional force on the object (called air resistance) with upward direction (opposite to the motion of free fall) and whose magnitude is proportional to the speed of the object.
Therefore, it turns out that as the object falls, its speed increases, and therefore the air resistance acting against it increases too; as a result, the at some point the air resistance becomes equal (in magnitude) to the force of gravity: when this happens, the net acceleration of the object becomes zero, and so the speed of the object does not increase anymore. This speed reached by the object is called terminal velocity.