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Katena32 [7]
3 years ago
10

For the graph above, what is the independent variable? What is the dependant variable?

Physics
1 answer:
posledela3 years ago
3 0
Time/sec. the x-axis is always the independent variable.
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You have a rock sample and analyze it for the presence of radioactive isotopes in order to determine when it was formed. You fin
Firdavs [7]

Answer:

the decay of half of the nuclei only a half-life has passed ,  b) in rock time it is 1 108 years

Explanation:

The radioactive decay is given by

         N = N₀ e^{\lambda t}

If half of the atoms have decayed

       ½ N₀ = N₀ e^{\lambda t}

       ½ = e^{\lambda t} ₀

       Ln 0.5 = - λ t

       t = - ln 0.5 /λ

The definition of average life time is

      T_{1/2}= ln 2 / λ

       λ = ln 2 /  T_{1/2}

       λ = 0.693 / 100 10⁶

       λ = 0.693 10⁻⁸ years

We replace

       t = -ln 0.5 / 0.693 10⁻⁸

       t = 10⁸ years

We see that for the decay of half of the nuclei only a half-life has passed

b) in rock time it is 1 108 years

8 0
3 years ago
What is conflict resolution?
enot [183]
Conflict resolution is conceptualized as the methods and processes involved in facilitating the peaceful ending of conflict and retribution.
7 0
3 years ago
Define a dipole. Hence, write the expression for calculating the electric moment of a dipole​
Aleksandr-060686 [28]

Answer:

Explanation:

An electric dipole is formed by two point charges +q and −q connected by a vector a. The electric dipole moment is defined as p = qa

4 0
1 year ago
Dos cargas puntuales están fijas en el eje x: q1 = 6.0µC está en el origen, O, con x1 = 0.0 cm, y q2 = –3.0 µC está situada en e
erik [133]

Answer:

E_total = 1.30 10¹⁰ C / m²

Explanation:

The intensity of the electric field is

     E = k q / r²

on a positive charge proof

The total electric field at the midpoint is

as q₁= 6 10⁻⁶ C the field is outgoing to the right

for charge q₂ = -3 10⁻⁶ C, the field is directed to the right, therefore

E_total = E₁ + E₂

E_total = k q₁ / r₁² + k q₂ / r₂²

r₁ = r₂ = r = 4 10⁻² m

E_total = k/r² (q₁ + q₂)

 we calculate

E_total = 9 10⁹ / (4 10⁻²)²   (6.0 10⁻⁶ +3.0 10⁻⁶)

E_total = 1.30 10¹⁰ C / m²

8 0
3 years ago
A proton moving at 8.9 × 106 m/s through a magnetic field of 0.96 T experiences a magnetic force of magnitude 3.8 × 10−13 N. Wha
goblinko [34]

Answer: 15.66 °

Explanation: In order to solve this proble we have to consirer the Loretz force for charge partcles moving inside a magnetic field. Thsi force is given by:

F=q v×B = qvB sin α where α is teh angle between the velocity and magnetic field vectors.

From this expression and using the given values we obtain the following:

F/(q*v*B) = sin α

3.8 * 10^-13/(1.6*10^-19*8.9*10^6* 0.96)= 0.27

then  α =15.66°

8 0
3 years ago
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