What is the molarity of a solution containing 9.478 grams of RuCl3 in enough water to make 1.00 L of solution?

1 answer:

4 0

Molar mass RuCl3 = 207.4290 g/mol

number of moles

9.478 / 207.4290 => 0.0456 moles

M = n / V

M = 0.0456 / 1.00 (L)

= 0.0456 M

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