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Ludmilka [50]
4 years ago
7

Two plane mirrors stand facing each other, 3.08 m apart, and a woman stands between them. The woman faces one of the mirrors fro

m a distance of 1.30 m and holds her left arm out to the side of her body with the back of her left hand facing the closer mirror.(a) What is the apparent position of the closest image of her left hand, measured perpendicularly from the surface of the mirror in front of her?
_____ m behind the nearest mirror

(b) Does it show the palm of her hand or the back of her hand?
_____

(c) What is the position of the next closest image?
_____ m behind the nearest mirror

(d) Does it show the palm of her hand or the back of her hand?
_____

(e) What is the position of the third closest image?
_____ m behind the nearest mirror

(f) Does it show the palm of her hand or the back of her hand?
_____

Physics
2 answers:
kolbaska11 [484]4 years ago
7 0

Answer:

A. stop or slow down

Explanation:

Svetllana [295]4 years ago
6 0

Answer:

A) 1.3m

B) it shows the back of her hand

C) 4.86m

D) it shows the palm of her hand

E) 7.46m

F) it shows the back of her hand.

Explanation:

Detailed explanation is shown in the illustrative diagram below.

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Answer:

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blagie [28]

Answer:

A and D

Explanation:

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8 0
3 years ago
1. The acronym AUDIENCE serves to remind you of what to consider when analyzing an audience. In the acronym, what does the C sta
Tom [10]
The correct answers are as follows:
1. D [CONTEXT]
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A: Analysis
U: Understanding
D: Demographic
I: Interest
E: Enviroment
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C: Context
E: Expectation
The acronyms is used in speech presentation to consider and analyse the audience needs so that a speaker will be able to satisfy these needs.
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3. CREATIVE STRATEGIES CAN HELP ENHANCE CREATIVITY DURING THE DESIGN PROCESS
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7 0
3 years ago
Read 2 more answers
Light of wavelength 578.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 62.5 cm from the slit.
yaroslaw [1]

Answer:

80.6\mu m

Explanation:

When light passes through a narrow slit, it produces a diffraction pattern on a distant screen, consisting of several bright fringes (constructive interference) alternated with dark fringes (destructive interference).

The formula to calculate the position of the m-th maximum in the diffraction pattern produced in the screen is:

y=\frac{m\lambda D}{d}

where

y is the distance of the m-th maximum from the central maximum (m = 0)

\lambda is the wavelength of light used

D is the distance of the screen from the slit

d is the width of the slit

In this problem, we have:

\lambda=578.0 nm = 578\cdot 10^{-9} m is the wavelength

D = 62.5 cm = 0.625 m is the distance of the screen

We know that the distance between the third order maximum (m=3) and the central maximum is 1.35 cm (0.0135 m), which means that

y_3 = 0.0135 m

For

m = 3

Therefore, rearranging the equation for d, we find the width of the slit:

d=\frac{m\lambda D}{y_3}=\frac{(3)(578\cdot 10^{-9})(0.625)}{0.0135}=80.3\cdot 10^{-6} m=80.6\mu m

8 0
4 years ago
What is imperceptible human motion?
castortr0y [4]
Unable to be noticed or not felt because of feeling slight
3 0
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