A pitcher throws a 142 g baseball, which accelerates at a speed of 9 m/s^2. How much force does the pitcher apply to the ball?

Chemistry

2 answers:

VLD [36.1K]3 years ago

6 0

Answer:

<h3>The answer is 1.28 N</h3>

Explanation:

The force acting on an object given the mass and acceleration we use the formula

<h3>force = mass × acceleration</h3>

From the question

mass = 142 g = 0.142 kg

acceleration = 9 m/s²

We have

force = 0.142 × 9 = 1.278

We have the final answer as

Hope this helps you

Andreas93 [3]3 years ago

6 0

Answer:

1.28

Explanation:

In order for you to get the force you have to multiply the mass & acceleration. The baseball mass is 142 g and the acceleration is 9. So you will calculate 0.142 x 9 and that will give you 1.278. You will then round the 7 to an 8 and then you get the answer 1.28.

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If 2.0 g of copper(II) chloride react with excess sodium nitrate, what mass of sodium chloride is formed in this double replacem

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<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

CuCl₂ + 2 NaNO₃ → Cu(NO₃)₂ + 2 NaCl

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

CuCl₂: 1 mole
NaNO₃: 2 moles
Cu(NO₃)₂ : 1 mole
NaCl: 2 moles

The molar mass of the compounds is:

CuCl₂: 134.44 g/mole
NaNO₃: 85 g/mole
Cu(NO₃)₂ : 187.54 g/mole
NaCl: 58.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

CuCl₂: 1 mole ×134.44 g/mole= 134.44 grams
NaNO₃: 2 moles ×85 g/mole= 170 grams
Cu(NO₃)₂ : 1 mole ×187.54 g/mole= 187.54 grams
NaCl: 2 moles ×58.45 g/mole= 116.9 grams

<h3>Mass of NaCl formed</h3>

The following rule of three can be applied: If by stoichiometry of the reaction 134.44 grams of CuCl₂ form 116.9 grams of NaCl, 2 grams of CuCl₂ form how much mass of NaCl?

$mass of NaCl=\frac{2 grams of CuCl_{2}x116.9 grams of NaCl }{134.44grams of CuCl_{2}}$