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sammy [17]
2 years ago
9

Describe atleast 3 types of effects that a toxic substance can have on the body

Chemistry
1 answer:
nikklg [1K]2 years ago
3 0
Chemicals cancer smoking
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How does water’s high specific heat capacity affect large lakes?
mixas84 [53]

Answer:

B The water at the bottom of the lake will never freeze

Explanation:

Its simple

5 0
3 years ago
A chemist needs to make 250 mL of a 2.50 M aqueous solution of ammonium hydroxide from a 6.00 M ammonium hydroxide solution. How
Furkat [3]

Answer:

250 mL (total solution)  = 104 mL (stock solution)  + 146 mL (water)

Explanation:

Data Given

M1 = 6.00 M

M2 = 2.5 M

V1 = 250 mL

V2 = ?

Solution:

As the chemist needs to prepare 250 mL of solution from 6.00 M ammonium hydroxide solution to prepare a 2.50 M aqueous solution of ammonium hydroxide.

Now

first he have to determine the amount of ammonium hydroxide solution that will be taken from6.00 M ammonium hydroxide solution

For this Purpose we use the following formula

                    M1V1=M2V2

Put values from given data in the formula

                   6 x V1 = 2.5 x 250

Rearrange the equation

                   V1 = 2.5 x 250 /6

                    V1 = 104 mL

So 104 mL is the volume of the solution which we have to take from the 6.00 M ammonium hydroxide solution to prepare 2.5 M  aqueous solution of ammonium hydroxide

But we have to prepare 250 mL of the solution.

so the chemist will take 104 mL from 6.00 M ammonium hydroxide solution and have to add 146 mL water to make 250 mL of new solution.

in this question you have to tell about the amount of water that is 146 mL

250 mL (total solution)  = 104 mL (stock solution)  + 146 mL (water)

7 0
3 years ago
What is the ph of a 0.014 M HCL solution?
Allushta [10]

Answer:

pH = 1.853

Explanation:

For every mole of hydrochloric acid, one mole of hydronium ion is required. Thus, in order to neutralize 0.014 moles of HCL, 0.014 moles of hydronium is required.

[H_3O^+] = [HCl] = 0.014

pH  = -log [H^+] = -log [H_3O^+]

Substituting the available values in above equation, we can say that   the pH of the solution is equal to

- log (0.014)

pH = 1.853

pH of a 0.014 M HCL solution = 1.853

8 0
3 years ago
8. The standard enthalpy of formation of RbF(s) is –557.7kJ/mol and the standard enthalpy of formation of RbF(aq, 1 m) is –583.8
garri49 [273]

Explanation:

Given

The enthalpy of formation of RbF (s) is –557.7kJ/mol

The standard enthalpy of formation of RbF (aq, 1 m) is –583.8 kJ/mol

The enthalpy of solution of RbF = Enthalpy of RbF (aq) - Enthalpy of formation of RbF (s)

= -583.8 - (-557.7)  kJ/mol

= -26.1 kJ/mol

The enthalpy is negative which means that the temperature will rise when RbF is dissolved.

3 0
3 years ago
How many grams are in 4.5 moles of NaF?
Ilia_Sergeevich [38]

Answer:

3139542g

Explanation:

That's because if you talk about

4.5

moles of sodium fluoride, you would get a really absurd number of grams.

6 0
2 years ago
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