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Taya2010 [7]
2 years ago
8

What is/are the energy transformation(s) that take place when using a wind turbine to generate usable energy?

Physics
1 answer:
Cerrena [4.2K]2 years ago
4 0

Answer:

the answer is C

Explanation:

C) friction - mechanical - electrical

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What is the force on a person’s hand, which is using a rope to accelerate a 5 kg block upward with an acceleration of 2.2 m/s 2
slavikrds [6]

Answer:

F = 11 N

Explanation:

Given,

Mass of a block, m = 5 kg

Acceleration of the block, a = 2.2 m/s²

We need to find the force on the person's hand. Let it is F. We know that force is given by the product of mass and acceleration as follows :

F = ma

F = 5 kg × 2.2 m/s²

F = 11 N

So, the force on a person's hand is 11 N.

5 0
3 years ago
Define Archemedics principle?​
azamat

Answer:

Archimedes' principle states that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially, is equal to the weight of the fluid that the body displaces. Archimedes' principle is a law of physics fundamental to fluid mechanics. It was formulated by Archimedes of Syracuse.

6 0
3 years ago
If two is company and three is a crowd, what is 4 and 5?
LiRa [457]

4 and 5 is 9

(4 + 5)

4 0
3 years ago
Read 2 more answers
BRAINLIESTTT!! HELP ME!!!
likoan [24]

The efficiency of the scissor is 200%.

<u>Explanation:</u>

Efficiency is defined as the ratio of output of any instrument or device or machine to the input supplied to it. So the greater the output the greater will be the efficiency of the device.

As here the work done by us on the system is said to be 10 J so this will be equal to the input work done on the system. And the work done by the system i.e., the scissor is 20 J, so this will be the output work.

So, the efficiency is the ratio of output to input as shown below.

Efficiency = (\frac {20} {10} ) \times 100 = 200

So, the efficiency of the scissor is 200%.

6 0
3 years ago
(a) What is the acceleration of gravity on the surface of the Moon? The mass of the moon is 7.35 x 1022 kg and its radius is 1.7
Liono4ka [1.6K]

Answer:

Part a)

a = 1.62 m/s/s

Part b)

a = 3.70 m/s/s

Explanation:

Part A)

Acceleration due to gravity on the surface of moon is given as

a = \frac{GM}{R^2}

here we know that

M = 7.35 \times 10^{22} kg

R = 1.74 \times 10^6 m

now we have

a_g = \frac{(6.67 \times 10^{-11})(7.35 \times 10^{22})}{(1.74 \times 10^6)^2}

a_g = 1.62 m/s^2

Part B)

Acceleration due to gravity on surface of Mercury is given as

a = \frac{GM}{R^2}

here we know that

M = 3.30 \times 10^{23} kg

R = 2.44 \times 10^6 m

now we have

a_g = \frac{(6.67 \times 10^{-11})(3.30 \times 10^{23})}{(2.44 \times 10^6)^2}

a_g = 3.70 m/s^2

8 0
3 years ago
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