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Nastasia [14]
3 years ago
9

William Herschel thought that the Sun and Earth were roughly at the center of the great grouping of stars we call the Milky Way.

Today we know this is not the case. What was a key reason that Herschel did not realize our true position in the Milky Way?
Physics
2 answers:
balu736 [363]3 years ago
3 0

Answer:

Explained

Explanation:

William Herschel thought that the Sun and Earth were roughly at the center of the great grouping of stars we call the Milky Way. He could say so because he was only able to see a small part of the galaxy. This was because of the fact that dust extended throughout the disk of the galaxy, making visibility very low.

Serjik [45]3 years ago
3 0

Answer:

William Herschel's Theory (Heliocentrism)

Explanation:

It was in 1783, when William Herschel examined the stars using his handmade telescope to figure out the shape of the galaxy. As a result of this examination, he concluded that the shape of our Milky Way was that of a 'disk' and that the sun was positioned in the center of this disk.

The reason he came to such a conclusion was that to him the Earth appeared to be 'amidst of several other stars' and when he worked out for the magnitudes of these stars the resulted figures were same in every direction. Therefore, based on these findings he concluded that the Earth is positioned somewhat near to the 'center' of the Milky Way.

Later on it was revealed that there were two errors in his findings;

  1. The magnitude is not considered as a reliable means to measure the distance of the stars.
  2. He was unable to keep in consideration the dark areas containing nebulae which blocked the view to the center of the galaxy and he thought of them as the vacant spaces.

<em>Nebulae:  </em>Plural of Nebula (Latin for cloud or fog). A nebula is initially referred to any dispersed astronomical object, including galaxies beyond Milky Way.

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Scientific evidence documents the pattern of evolution. The evidence exists in a variety of categories. What are these categorie
Sauron [17]

Answer:

Explanation:

Scientific evidence takes note of the pattern of evolution. The evidence exists in a variety of categories, including direct observation of evolutionary change, the fossil record, homology, and biogeography.

Examples of the categories with their respective examples are:

Direct observation of evolutionary change: Development of drug resistant bacteria

Fossil record: Discovery of transitional forms of horses, Discovery of shells of extinct species

Homology: Similarities in mammalian forelimbs, Same genetic code in fireflies and tobacco plants, Vestigial pelvis in right whales

Biogeography: Similarity of endemic island species to nearby mainland species, The high concentration of marsupial species in Australia

3 0
3 years ago
A simple pendulum with length L is swinging freely with
Trava [24]

Answer:

it will be 1/√2 of its original period.

Explanation:

8 0
3 years ago
You drive 6.00 km at 50.0 km/h and then another 6.00kmat 900 km/h Your average speed over
Cerrena [4.2K]

Explanation:

average speed = total distance travelled / total time travelled

time to travel the first 6km: 6 / 50 = 3/25 (h)

time to travel the next 6km: 6 / 90 = 1/15 (h)

[I think there's problem in the question 'cause 900km/h sounds impossible for normal person to travel in normal condition]

The total time: 3/25 + 1/15 = 14/75 (h)

Average speed over the 12 km drive will be:

\frac{12}{ \frac{14}{75} }  =  \frac{450}{7}  = 64.3 \: km{h}^{ - 1}

8 0
3 years ago
As more babies are piled into a shopping cart, and the velocity stays the same, what happens to its momentum?
vagabundo [1.1K]
The momentum would increase assuming the velocity stays the same. P=Mv
7 0
2 years ago
If a 20 g cannonball is shot from a 5 kg cannon with a velocity of 100
balu736 [363]

Strange as it may seem, the statement in the question appears to be <em>TRUE</em>.  

-- Before the shot, neither the cannon nor the ball is moving, so their combined momentum is zero.  

-- Since momentum is conserved, we know immediately that their combined momentum AFTER the shot also has to be zero.

-- (20g is rather puny for a "cannonball" ... about the same weight as four nickels. But we'll take your word for it and just do the Math and the Physics.)

-- Momentum = (mass) x (velocity)

After the shot, the momentum of the cannonball is

(0.02 kg) x (100 m/s ==> that way)

Momentum of the ball = 2 kg-m/s ==> that way.

-- In order for both of them to add up to zero, the momentum of the cannon must be (2 kg-m/s this way <==) .

Momentum of cannon = (5 kg) x (V m/s this way <==)

2 kg-m/s this way <== = (5 kg) x (V m/s this way <==)

Divide each side by (5 kg):

V m/s  =  (2/5) m/s this way <==

Speed of recoil of the cannon = <em>-- 0.4 m/s</em>

3 0
3 years ago
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