Question

The Kw of water varies with temperature. Calculate the pH of water at 46⁰C with a Kw = 1.219 x 10-14. Show all calculations leading to an answer.

Answer 1

Kw = 1.219x10⁻¹⁴

kw = [H⁺] x [OH⁻]

in water [H⁺] = [OH⁻] therefore:

[H⁺] = √ kw

[H⁺] = √ 1.219x10⁻¹⁴

[H⁺] = 1.104x10⁻⁷

pH = - log [H⁺]

pH = - log [ 1.104x10⁻⁷ ]

pH = 6.95

hope this helps!