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Anon25 [30]
3 years ago
15

If a forcé has a negativa values such as -100N, that means

Physics
1 answer:
Lisa [10]3 years ago
6 0
Its negative
:)))))))))))))
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Find the magnitude of the resultant forces 6N and 8N inclined at an angle 240° to each<br>other.​
Nana76 [90]

Answer:

F = 7.2N

Explanation:

The resultant of two forces acting at some angle is given by using the vector addition as given below

F =√F1^2+F2^2+2F1F2cosθ

Where F1 = 6N and F2 = 8N

θ = 240°

Substituting the values into the equation above

F = √ 6^2+8^2+ 2(6×8)cos240

F =√ 36+64+96cos240

F = √ 100+96 ×-0.5

F = √ 100-48

F = √ 52

F = 7.211

F = 7.2N

7 0
3 years ago
At the surface of Venus the average temperature is a balmy 460∘C due to the greenhouse effect (global warming!), the pressure is
yanalaym [24]

Answer:

a) 86 atm

b) 86 atm

c) 645 m/s

Explanation:

See attachment for calculations on how i arrived at the answer

8 0
3 years ago
PLEASE ANSWER ASAP BEFORE MY TEACHER AND MY MOM KILLES ME PLEASE ASAP
yawa3891 [41]
The red at the bottom is just the holder for the beaker. It’s not apart of the density.
6 0
3 years ago
Read 2 more answers
The question states: two large, parallel conducting plates are 12cm
AnnZ [28]

Answer:

1. 24375 N/C

2. 2925 V

Explanation:

d = 12 cm = 0.12 m

F = 3.9 x 10^-15 N

q = 1.6 x 10^-19 C

1. The relation between the electric field and the charge is given by

F = q E

So, E=\frac{F}{q}

E=\frac{3.9 \times 10^{-15}}{1.6 \times 10^{-19}}

E = 24375 N/C

2. The potential difference and the electric field is related by the given relation.

V = E x d

where, V be the potential difference, E be the electric field strength and d be the distance between the electrodes.

By substituting the values, we get

V = 24375 x 0.12 = 2925 Volt

6 0
3 years ago
A bicyclist starts at rest and speeds up to 30 m/s while accelerating at 4 m/s^2. Determine the distance traveled.
raketka [301]

Answer:

Distance, d = 112.5 meters

Explanation:

Initially, the bicyclist is at rest, u = 0

Final speed of the bicyclist, v = 30 m/s

Acceleration of the bicycle, a=4\ m/s^2

Let s is the distance travelled by the bicyclist. The third equation of motion is given as :

v^2-u^2=2as

s=\dfrac{v^2-u^2}{2a}

s=\dfrac{(30)^2}{2\times 4}

s = 112.5 meters

So, the distance travelled by the bicyclist is 112.5 meters. Hence, this is the required solution.

6 0
3 years ago
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