The resultant displacement of the man is 109.77 km in the direction N60°E.
<h3>Displacement</h3>
Displacement is the distance travelled in a specified direction.
To calculate displacement, the straight line from starting point to end point of travel is taken and calculated.
<h3>Resultant displacement of the man </h3>
In the example above, a man walks 95 km, East, then 55 km, north.
The two distances form a right-angled triangle with two sides 95 and 55 units. The hypotenuse gives the resultant displacement, D.
Using Pythagoras rule:
D^2 = 95^2 + 55^2
D^2 = 12050
D = 109.77
Thus, the resultant displacement is 109.77 km
To calculate the direction:
Let the direction be y
y + x = 90°
tan x = 55/95
tanx x = 0.578
x = 30°
Then, y = 90 - 30
y = 60°
Therefore, the resultant displacement of the man is 109.77 km in the direction N60°E.
Learn more about displacement at: brainly.com/question/321442
The answer is D. Because the boy jump 3 high
4
Just divide 12 by 3, so if it takes 3 seconds, then every second, it goes up 4.
Answer:
v = 7.67 m/s for L= 1m
Explanation:
Let's use the conservation of mechanical energy, at the highest point and the lowest point
Initial. Vertical ruler
Em₀ = mg h
Final. Just before touching the floor
= K = ½ I w²
Em₀ = 
m g h = ½ I w²
The moment of inertia of a ruler that turns on one end is
I = 1/3 m L²
Let's replace
m g h = ½ (1/3 m L²) w²2
g h = 1/6 L² w²
They ask for the speed of the end so the height h is equal to the length of the ruler
g L = 1/6 L² w²
The linear and angular variables are related
v = w r
w = v / r
In this case the point of interest a in strangers r = L
g L = 1/6 L² v² / L²
v = √ 6 g L
Let's calculate
Assume that the length of the meter is L = 1 m
v = √ (6 9.8 1)
v = 7.67 m/s
a) The mass of the ship is 
b) The ship has a larger momentum than the shell
Explanation:
a)
The momentum of an object is given by:

where
m is the mass of the object
v is its velocity
For the ship in this problem, we have
is the momentum
is the velocity
Solving for m, we find the mass of the ship:

b)
The momentum of the artillery shell is given by

where
m is its mass
v is its velocity
For the shell in this problem,
m = 1100 kg
v = 1200 m/s
Substituting,

So, we see that the ship has a larger momentum.
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