If a forcé has a negativa values such as -100N, that means

B)A man walks 95 km, East, then 55 km, north. Calculate his RESULTANT

Varvara68 [4.7K]

The resultant displacement of the man is 109.77 km in the direction N60°E.

<h3>Displacement</h3>

Displacement is the distance travelled in a specified direction.

To calculate displacement, the straight line from starting point to end point of travel is taken and calculated.

<h3>Resultant displacement of the man </h3>

In the example above, a man walks 95 km, East, then 55 km, north.

The two distances form a right-angled triangle with two sides 95 and 55 units. The hypotenuse gives the resultant displacement, D.

Using Pythagoras rule:

D^2 = 95^2 + 55^2

D^2 = 12050

D = 109.77

Thus, the resultant displacement is 109.77 km

To calculate the direction:

Let the direction be y

y + x = 90°

tan x = 55/95

tanx x = 0.578

x = 30°

Then, y = 90 - 30

y = 60°

Therefore, the resultant displacement of the man is 109.77 km in the direction N60°E.

Learn more about displacement at: brainly.com/question/321442

8 0

2 years ago

A boy jumps from a wall 3m high. What is an estimate of the change in momentum of the boy when he lands without rebounding?

EastWind [94]

The answer is D. Because the boy jump 3 high

8 0

2 years ago

If u speed up from rest to 12 m/s in 3 seconds, what is your acceleration

irakobra [83]

4

Just divide 12 by 3, so if it takes 3 seconds, then every second, it goes up 4.

4 0

3 years ago

Read 2 more answers

A meter stick is held vertically with one end on the floor and is then allowed to fall. Find the speed of the other end just bef

stich3 [128]

Answer:

v = 7.67 m/s for L= 1m

Explanation:

Let's use the conservation of mechanical energy, at the highest point and the lowest point

Initial. Vertical ruler

Em₀ = mg h

Final. Just before touching the floor

$Em_{f}$ = K = ½ I w²

Em₀ = $Em_{f}$

m g h = ½ I w²

The moment of inertia of a ruler that turns on one end is

I = 1/3 m L²

Let's replace

m g h = ½ (1/3 m L²) w²2

g h = 1/6 L² w²

They ask for the speed of the end so the height h is equal to the length of the ruler

g L = 1/6 L² w²

The linear and angular variables are related

v = w r

w = v / r

In this case the point of interest a in strangers r = L

g L = 1/6 L² v² / L²

v = √ 6 g L

Let's calculate

Assume that the length of the meter is L = 1 m

v = √ (6 9.8 1)

v = 7.67 m/s

7 0

2 years ago

What is the mass of a large ship that has a momentum of 1.60×109kg·m/s, when the ship is moving at a speed of 48.0 km/h? (b) Com

erastova [34]

a) The mass of the ship is $1.2\cdot 10^8 kg$

b) The ship has a larger momentum than the shell

Explanation:

a)

The momentum of an object is given by:

$p=mv$

where

m is the mass of the object

v is its velocity

For the ship in this problem, we have

$p=1.60\cdot 10^9 kg m/s$ is the momentum

$v=48.0 km/h \cdot \frac{1000 m/km}{3600 s/h}=13.3 m/s$ is the velocity

Solving for m, we find the mass of the ship:

$m=\frac{p}{v}=\frac{1.60\cdot 10^9}{13.3}=1.2\cdot 10^8 kg$

b)

The momentum of the artillery shell is given by

$p=mv$

where

m is its mass

v is its velocity

For the shell in this problem,

m = 1100 kg

v = 1200 m/s

Substituting,

$p=(1100)(1200)=1.32\cdot 10^6 kg m/s$

So, we see that the ship has a larger momentum.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

6 0

3 years ago