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Roman55 [17]
2 years ago
8

Which solution whose POH is 12

Chemistry
1 answer:
lesya692 [45]2 years ago
3 0

Answer:

d

Explanation:

H3O =1×10_12=12 ooh is 12

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What is the concentration of a dextrose solution prepared by diluting 16 mL of a 1.0 M dextrose solution to 25 mL using a 25 mL
seraphim [82]

Answer:

0.64 M

Explanation:

Step 1: Given data

  • Initial concentration (C₁): 1.0 M
  • Initial volume (V₁): 16 mL
  • Final concentration (C₂): ?
  • Final volume (V₂): 25 mL

Step 2: Calculate the final concentration of the dextrose solution

We want to prepare a diluted solution from a concentrated one. We can find the final concentration using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁ / V₂

C₂ = 1.0 M × 16 mL / 25 mL

C₂ = 0.64 M

4 0
3 years ago
Carbon monoxide and chlorine gas react to produce COCl2 gas. The Kp for the reaction is 1.49 × 108 at 100.0 °C: In an equilibriu
Eva8 [605]

Answer:

Explanation:

Solution:

For the equilibrium

The equilibrium constant is defined in terms of partial pressure:

Introducing the numerical data given for partial pressureof carbon monoxide 0 and chlorine 12, also the value for equilibrium constant:

Answer:

The partial pressureof the product, phosgene (COCl2), is 29.4atm

5 0
3 years ago
Read 2 more answers
The unbalanced equation for the reduction of copper(I) sulfide with oxygen is given below. What mass of copper is produced from
uranmaximum [27]

<u>Answer:</u> The mass of copper produced is 7.12 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of copper (I) sulfide = 8.80 g

Molar mass of copper (I) sulfide = 156.2 g/mol

Putting values in equation 1, we get:

\text{Moles of copper (I) sulfide}=\frac{8.80g}{156.2g/mol}=0.056mol

The chemical equation for the reaction of copper (I) sulfide and oxygen gas follows:

Cu_2S+O_2\rightarrow 2Cu+SO_2

By Stoichiometry of the reaction:

1 mole of copper (I) sulfide produces 2 moles of copper

So, 0.056 moles of copper (I) sulfide will produce = \frac{2}{1}\times 0.056=0.112mol of copper

Now, calculating the mass of copper from equation 1, we get:

Molar mass of copper = 63.55 g/mol

Moles of copper = 0.112 moles

Putting values in equation 1, we get:

0.112mol=\frac{\text{Mass of copper}{63.55g/mol}\\\\\text{Mass of copper}=(0.112mol\times 63.55g/mol)=7.12g

Hence, the mass of copper produced is 7.12 grams

6 0
3 years ago
Is precipitate in water an electrolyte solution
vagabundo [1.1K]
When no ions are produced, or the ion content is low, the solute is a non-electrolyte. Non-electrolytes do not conduct electricity or conduct it to a very small degree. In an aqueous solution a strong electrolyte is considered to be completely ionized, or dissociated, in water, meaning it is soluble
4 0
3 years ago
2. The Food and Drug Administration (FDA) mandates that all vinegar sold in the United States must have a minimum concentration
Scilla [17]

Answer:

The minimum molarity of acetic acid in vinegar according to given standards is 0.6660 mol/L.

Explanation:

4% acetic acid by mass means that 4 gram of acetic acid in 100 g solution.

Given that density of the vinegar is same is that of water =  1 g/mL

Mass of the vinegar solution = 100 g

Volume of the vinegar solution = V

Density=\frac{Mass}{Volume}

1 g/mL=\frac{100 g}{V}

V = 100 mL = 0.1 L

Moles of acetic acid =\frac{4 g}{60.052 g/mol}=0.0666 mol

Molarity=\frac{\text{Moles of solute}}{\text{Volume of solution(L)}}

M=\frac{0.0666 mol}{0.1 L}=0.6660 mol/L

The minimum molarity of acetic acid in vinegar according to given standards is 0.6660 mol/L.

4 0
3 years ago
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