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Grace [21]
3 years ago
9

1. What did you observe about the magnitudes of the forces on the two charges? Were they the same or different? Does your answer

depend on whether the charges were of the same magnitude or different? How does this relate to Newton’s 3rd law?
Physics
1 answer:
Aloiza [94]3 years ago
7 0

Answer:

Following are the solution to the given question:

Explanation:

Its strength from both charges is equivalent or identical. The power is equal. And it is passed down

F=\frac{kq_1q_2}{r^2}

Therefore, the extent doesn't rely on the fact that charges are the same or different. Newton's third law complies with Electrostatic Charges due to a couple of charges. They are similar in magnitude, and they're in the other way.

|F_{12}| = |F_{21}|

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Answer:

v = 1.98\ m/s

Explanation:

consider the mass of each train car be m

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u₁ = u₂ = u₃ = 1.8 m/s

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m₅ = m              u₅ = 0 (initial velocity )

final velocity

v₁ = v₂ = v₃ = v₄ = v₅ = v

using conservation of momentum

m₁u₁ + m₂u₂ + m₃u₃ + m₄u₄ + m₅u₅ = m₁v₁ + m₂v₂ + m₃v₃ + m₄v₄ + m₅v₅

m (1.8 + 1.8 + 1.8 +4.5) = 5 m v

v = \dfrac{9.9}{5}

v = 1.98\ m/s

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