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3 years ago

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A scientist collected data in 10 trials comparing tired students' and awake students' test scores. Trial Tired Average Score Awa

ke Average Score 1 34% 67% 2 56% 88% 3 60% 90% 4 58% 86% Which trial was the least precise and is unlikely to be reproducible?

2 answers:

RSB [31]3 years ago

8 0

Scores of trial 2,3 are more accurate while trail 1 is the least precise as well as un-reproducible.

Explanation:

The second rating is really similar to the first since Score 1 is 34 points, 64 points.

They measure the average as 34 + 67/2 = 50.5

Deviations from the defined values are determined as follows:

50.5-34 = 16.5 & 50.5-67 = -16.5

Then the total variance is = (16.5 + -16.5)/2 = 0.00

Calculating Rating 2 by the provided values: 56 percent, 88 percent.

We measure an average of 56 + 88/2 = 72.

Deviations from the specified values are determined as follows: 72-56 = 16, 72-88 =-16.

The maximum variations here are 0.00.

Calculation of Score 3 by the specified values: 60 percent, 90 percent.

Similarly, we will consider the Median as 60 + 90/2 = 75.

Deviations from this are 75-60 = 15, 75-90 = -15.

The maximum variations here are 0.00.

The assigned Score 4 is 58 per cent, 86 per cent and its average is 72 and its deviation is-14, while its average deviation is 0.

Result: Trail 1 has a high divergence, so it is less reliable.

lesantik [10]3 years ago

7 0

Answer:the answer is A- trail 1!

Explanation:have a great day and goodluck! :)

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GarryVolchara [31]

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4 years ago

A key lime pie in a 10.00 inch diameter plate is placed upon a rotating tray. Then, the tray is rotated such that the rim of the

juin [17]

Answer:

The angular distance in revolution is $revolution = 3.439 \ revolution$

The angular distance in radians is $\theta_{rad}= 21.6 \ radians$

The angular distance in degrees is $\theta =1238.04^o$

The angular size is $Z = \frac{2}{9} \pi \ radians$

Explanation:

From the question we are told that

The diameter is $d = 10 \ inches$

The distance moved by the rim is $D = 108 \ inches$

Generally the circumference of the pie plate is mathematically represented as

$C = \pi d$

Substituting the values

$C = 10 *3.142$

$= 31.42 \ inches$

The number resolution carried out by the pie plate is evaluated as

$revolution = \frac{D}{C}$

Substituting value

$revolution = \frac{108}{31.4}$

$revolution = 3.439 \ revolution$

The angular distance $\theta_{rad}$ is mathematically evaluated as

$\theta_{rad} = \frac{D}{r}$

Where r is the radius which is mathematically evaluated as

$r = \frac{d}{2} = \frac{10}{2} = 5 \ inches$

Substituting this into the equation for angular distance

$\theta_{rad} = \frac{108}{5}$

$\theta_{rad}= 21.6 \ radians$

The angular distance traveled in degrees is

$\theta = 3.439 *360$

$\theta =1238.04^o$

When the pie is cut into 9 equal parts

The angular size would be mathematically evaluated as

$Z = \frac{2\pi}{9}$

$Z = \frac{2}{9} \pi \ radians$

7 0

4 years ago

What should you do if your boat capsizes answers?

nalin [4]

Many of the boating fatalities take place after capsize, but a modest list of things to do before and after a capsize can minimize boat accidents and boat accident injuries.

Initially there is an significant list of thing to do before you even step on the boat:

1. Take the boat safety and water safely courses
2. Make certain that yourself and everyone else on the boat is wearing a well-fitting and safe life jacket.
3. Go over the place of the safety items with everyone on the boat as well as the location of the horn of the boat and the flare of the boat.
4. Paint bright color the hull of the boat in order to be seen easily from the air.

After a capsize, there are significant steps to make

1. Stay calm
2. Execute a head count and check everybody for injuries or immediate dangers.
3. Ensure that everyone has floatation device that coolers and other items that can be used.
4. Stay in the capsized boat unless dangerous.
5. Try to right the boat if someone has a knowledge on how to do so.
6. Use signal devices such as flares, bright colored life jacket, whistles, flashlights and mirror.
7. Try to reboard or climb onto it in order to get as much of your body out of the cold water as possible because treading water will ground to lose body heat sooner.
8. Do not waste energy and only signal when needed. Try to keep warm and stay strong<span />

6 0

3 years ago

A steel ball with mass m is suspended from the ceiling at the bottom end of a light, 17.0-m-long rope. The ball swings back and

iogann1982 [59]

Answer:

1. 18.25 m/s

2. 0 m/s

Explanation:

1.So the centripetal acceleration of the ball at this lowest point must be, taking gravity into account

$a_c = \frac{T - mg}{m} = \frac{3mg - mg}{m} = 2g$

The speed at this point would then be

$v^2 = a_c r = 2gr = 2*9.8*17 = 333.2$

$v = \sqrt{333.2} = 18.25 m/s$

2. Similarly, if T = mg, then the centripetal acceleration must be

$a_c = \frac{T - mg}{m} = \frac{mg - mg}{m} = 0$

As the ball has no centripetal acceleration, its speed must also be 0 as well.

6 0

4 years ago

Wagon wheel. While working on your latest novel about settlers crossing the Great Plains in a wagon train, you get into an argum

OverLord2011 [107]

Answer:

I = 16.7kgm²

Explanation:

Since, Torque is given by,

\tau = F*r = I*\alpha

here, I = Moment of inertia = ??

\alpha = angular acceleration of wheel = a/r

F = tangential tension acting on the wheel = T

a = acceleration of bag of sand = 2.95 m/s^2

r = radius of wheel = d/2 = 120/2 = 60 cm = 0.60 m

from force balance on sand bag,

mg - T = m*a

T = m*(g-a)

m = mass of sand bag = 20 kg

So, I = T*r/\alpha = m*(g-a)*r/(a/r)

Using known values:

I = 20*(9.81 - 2.95)*0.60/(2.95/0.60) = 16.74

I = 16.7 kgm² = Moment of inertia of wheel experimentally

also, Moment of inertia of wheel theoretically(I') = M*r²

given, M = mass of wheel = 70 kg

I' = 70*0.60²= 25.2 kgm² = Moment of inertia of wheel theoretically

7 0

3 years ago