A uniform metal bar of length 6m and mass 100kg rest with its upper end against a smooth vertical wall and with its lower end on
1 answer:
You might be interested in
Question is missing. Found on google:
<em>"Part A What is the acceleration of the ball? Express your answer to two significant figures and include the appropriate units. </em>
<em>Part B </em>
<em>What is the net force on the ball during the hit? </em>
<em>Express your answer to two significant figures and include the appropriate units."</em>
Solution:
A)
The acceleration of the ball is given by
where
v = 12 m/s is the final velocity
u = 0 is the initial velocity (the ball is stationary)
t = 2.0 ms = 0.002 s is the time of contact
Substituting,
B)
The force on the ball can be found by using Newton's second law:
where
m = 140 g = 0.14 kg is the mass of the ball
is the acceleration
Substituting,
The centripetal acceleration of an object is given by the relation,
where Ac = centripetal acceleration =
R = radius of rotation = 15 m
V = speed of astronaut
Hence,
solving this we get, V = 38.34 m/s