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VashaNatasha [74]
3 years ago
6

The density of glycerin is 1.26 g/cm3. Which substance will sink in glycerin?

Physics
2 answers:
adell [148]3 years ago
8 0

Answer:aluminum (2.70 g/cm3)

Explanation:

Mademuasel [1]3 years ago
7 0
The answer to your question is aluminum.
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Oop i spill grape jucie on the carpet my mom gonna kill me :(
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Answer:

Wow that is tough. Go hide lol

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The nucleus is positive in charge because it contains?
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Protons and neutrons
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- A particular light source gives off light waves with a measured wavelength of
skad [1K]

Answer:

f = 1.5 x 10¹⁵ Hz

Explanation:

Light is an electromagnetic wave and we know that the speed of light is a constant which is 

3 x 10⁸ m/s.

Knowing this; v = λ x f

λ = wavelength

f= frequency of light

v = seed of light

f = v/λ

f =  3 x 10⁸m/s / 2.0 x 10-⁷ m

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2 years ago
During the day, Susan notices that the wind is blowing onshore at the beach. What is this called?
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For the answer to the question above, it is A. Sea Breeze or <span>on shore, </span>breeze<span> is a gentle wind blowing from the </span>sea<span> toward land, that develops over bodies of water near land due to differences in air pressure created by their different heat capacity. It is a common occurrence along coasts during the morning as solar radiation heats the land more quickly than the water.</span>
6 0
3 years ago
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The charge of an electron is -1.60x10-19 C. A current of 1 A flows in a wire carried by electrons. How many electrons pass throu
faltersainse [42]

Answer: 6.241\times 10^{18} electrons pass through a cross section of the wire each second.

Explanation:

According to mole concept:

1 mole of an atom contains 6.022\times 10^{23} number of particles.

Given : Charge on 1 electron = 1.6\times 10^{-19}C

Charge on 1 mole of electrons = 1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C

To calculate the charge passed we use the equation:

I=\frac{q}{t}

where,

I = current passed = 1 A

q = total charge = ?

t = time required = 1 sec

Putting values in above equation, we get:

1A=\frac{q}{1s}\\\\q=1A\times 1s=1C

When 96500C of electricity is passed , the electrons passed = 6.022\times 10^{23}

1 C of electricity is passed , the electrons passed = \frac{6.022\times 10^{23}}{96500}\times 1C=6.241\times 10^{18}

Hence, 6.241\times 10^{18} electrons pass through a cross section of the wire each second.

4 0
3 years ago
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