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rosijanka [135]
2 years ago
14

Which statements about Thomas Sully's portraits are true?

Mathematics
1 answer:
Anastasy [175]2 years ago
4 0
Its b and a hope this helps
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Factorise<br>ab+cb+ad+cd​
sweet-ann [11.9K]

Answer:

Factorized abaabababba

Step-by-step explanation:

yeet

3 0
2 years ago
So confused pls help&gt;&gt;&gt;&gt; there’s a pic
Volgvan
25/4 is the right answer have a good day :)
3 0
2 years ago
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I need heeeeeelp please and thank you :)
Citrus2011 [14]
The answer the the question is A.
5 0
2 years ago
In rectangle abcd measure of angle d =(3x+15) measure b =(6x-42) find measure of angle a
slava [35]
5) So for parallelogram ABCD, ∠B ≅ ∠D, and ∠A ≅ ∠C. Further, ∠B and ∠A are supplementary (i.e., their sum is 180°), and ∠D and ∠C are also supplementary.
So, we have that m∠B = m∠D. Therefore, 
6x-42=3x+15\\3x=57\\x=19

Now, let's substitute for x back into the expression for either ∠B or ∠D to find it's angle measure.
m∠B = 6(19)-42=72
Now, remember that ∠B or ∠D are supplements of ∠A. 
So, m∠B + m∠A = 180°.
That means m∠A = 180° – 72° = 108°.
That seems reasonable, because A appears to be an obtuse angle.
6 0
3 years ago
A tank contains 300 liters of fluid in which 40 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu
bonufazy [111]

Answer:

A(t) = 300 -260e^(-t/50)

Step-by-step explanation:

The rate of change of A(t) is ...

A'(t) = 6 -6/300·A(t)

Rewriting, we have ...

A'(t) +(1/50)A(t) = 6

This has solution ...

A(t) = p + qe^-(t/50)

We need to find the values of p and q. Using the differential equation, we ahve ...

A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50

0 = 6 -p/50

p = 300

From the initial condition, ...

A(0) = 300 +q = 40

q = -260

So, the complete solution is ...

A(t) = 300 -260e^(-t/50)

___

The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.

6 0
2 years ago
Read 2 more answers
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