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lidiya [134]
3 years ago
7

Draw the beta-hydroxy Ketone Intermediate and final condensation product for the following Aldol Reaction: Yol 2200 1 equiv. 2 e

quiv
Chemistry
1 answer:
jeka943 years ago
6 0

Answer:

idktdhfff jxjf

Explanation:

nopefvffgh gfgg

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Which best describes an oxidizing agent?
stellarik [79]

Answer:B) a reactant that undergoes reduction

Explanation:

Oxidation reaction is defined as the reaction in which a substance looses electrons. The oxidation state of the substance increases during oxidation.

M\rightarrow M^++e^-

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced during reduction.

N^++e^-\rightarrow N

Overall reaction: M+N^+\rightarrow M^++N

The substance M which itself gets oxidized, reduces other and is called as reducing agent. The substance N which itself gets reduced, oxidizes other and is called as oxidizing agent.

6 0
3 years ago
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Theresa invested $5,000 in an account she expects will earn 7% annually. Approximately how many years will it take for the accou
Lady_Fox [76]
About 7-8 years More. The real answer would be 7.14285714286

3 0
3 years ago
Write any three acids which are used in our daily life. Also, write an application of each​
lidiya [134]
Sodium fluoride- to brush teeth
Citric acid- orange juice for breakfast
Sodium hydroxide- cleaning agent
3 0
2 years ago
What kind of charge would the hydrogen atoms have compared to the oxygen atom in the water molecule? Note: A water molecule 2 hy
Basile [38]
Since water molecules are polar. Unequal sharing of electrons between the elements that make it. The hydrogen atoms would experience a slight partial positive charge as the electron density is more close to the oxygen atom making it partially negative.
3 0
3 years ago
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A 0.885 M solution of KBr whose initial volume is 82.5 mL has more water added until its concentration is 0.500 M. What is the n
4vir4ik [10]

Answer:

V_2=146mL

Explanation:

Hello there!

In this case, since the equation for the calculation of dilutions is:

M_1V_1=M_2V_2

Whereas M is the molarity and V the volume, because the final concentration is lower than the initial. Thus, since we are asked to calculate the final volume, we solve for V2 as follows:

V_2=\frac{M_1V_1}{M_2}=\frac{0.885M*82.5mL}{0.500M}\\\\V_2=146mL

Best regards!

4 0
3 years ago
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