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Irina18 [472]
3 years ago
7

Juan told Sylvia he got a $0.50 raise this week and his new hourly rate will be $10.25 an hour. Sylvia wants to know what Juan’s

hourly rate was before his raise. Which equation and solution can be used to solve this problem? r minus 10.25 = 0.50: Add 10.25 to both sides. The answer is $10.75. r + 0.50 = 10.25: Subtract .50 from both sides. The answer is $9.75. r minus 0.50 = 10.25: Subtract .50 from both sides. The answer is $10.75 r + 10.25 = 0.50: Subtract .50 from both sides. The answer is $9.75.
Mathematics
2 answers:
makvit [3.9K]3 years ago
7 0

Answer:

b

Step-by-step explanation:

zhenek [66]3 years ago
6 0

Answer:

The correct answer is:

r + 0.50 = 10.25: Subtract .50 from both sides. The answer is $9.75.

This is because Juan got a $0.50 raise which means that his new rate will be $0.50 more than his original rate (r).

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Answer:

x° = 79°

z° = 101°

Step-by-step explanation:

6 0
2 years ago
Factor each expression.<br> 17. 5x -25
aleksandr82 [10.1K]
Answer:

~ 5(x-5)

Explanation:

~ Always find GCF to factorize a number, here it’s 5

~ Now inside the bracket the x stays the same but 25 divided by 5=5

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7 0
3 years ago
At a country concert, the ratio of the number of boys to girls is 2:7. If there are 250 more girls than boys, how many boys are
allsm [11]
We can setup an equation for this.

Boys to Girls = 2:7
Boys =  x
Girls = 250+x
Setup the ratio 
 x:(250+x) = 2:7
x / (250+x) = 2/7
7x = 500+2x
7x-2x = 500
x = 500/5 =100

There are 100 boys at the concert
6 0
2 years ago
Read 2 more answers
Do well-rounded people get fewer colds?
asambeis [7]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if people with less social contact get more colds than people who are involved in a variety of social activities.

For this, a sample of 276 healthy men and women was taken.

n₁= 96 had few social outlets

n₂= 105 had six or more activities

These two groups were exposed to the cold virus and the following proportions of individuals that got sick were obtained:

p'₁= 0.62 (62% of the people with few social outlets got sick)

p'₂= 0.35 (35% of the people with six or more activities got sick)

The study variables are X₁: number of people with few social outlets that got sick after being exposed to the cold virus, in a sample of 96, and X₂: number of people with six or more activities that got sick after being exposed to the cold virus, in a sample of 105.

You have to construct a 99% CI for the difference these two populations since there is no specific order given I'll estimate: p₁ - p₂

(p'₁ - p'₂) ± Z_{1-\alpha /2} * \sqrt{\frac{p'_1(1-p'_1)}{n_1} +\frac{p'_2(1-p'_2)}{n_2} }

Z_{1-\alpha /2}= Z_{0.995}= 2.586

(0.62-0.35) ± 2.586 \sqrt{\frac{0.62*0.38}{96} +\frac{0.35*0.65}{105} }

[0.094; 0.045]

With a 99% confidence level, you'd expect that the difference between the proportion of people with few social outlets that got sick and the proportion of people with six or more social activities that got sick after being exposed to the cold virus.

I hope it helps!

8 0
2 years ago
Write and solve the equation. Show all work.
GarryVolchara [31]
X/2-20=22
440 is your answer
6 0
2 years ago
Read 2 more answers
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