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Crank
3 years ago
6

Convert the following: 52 miles/hour to meters/second

Physics
1 answer:
Komok [63]3 years ago
5 0

Answer:

23.246 metres per second

Explanation:

divide the speed value by 2.237

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found the potential spring energy. not sure how to find the height of the block by knowing only the mass. found the weight of it
evablogger [386]

(h + .16) m g = 1/2 k x^2   total PE of block relative to where it stops

(h + .16) .82 * 9.8 = .5 * 120 * .16^2    PE released = PE of  spring

8.04 h + 1.29 = 1.536

h = (1.536 - 1.29) / 8.04 = .031 m = 3.1 cm

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4 years ago
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Which of the following statements is an accurate description of vibrations?
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3 years ago
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Two neutron stars are separated by a distance of 1.0 x 1012 m. They each have a mass of 1.0 x 1028 kg and a radius of 1.0 x 103
son4ous [18]

To develop this problem it is necessary to apply the concepts related to Gravitational Potential Energy.

Gravitational potential energy can be defined as

PE = -\frac{GMm}{R}

As M=m, then

PE = -\frac{Gm^2}{R}

Where,

m = Mass

G =Gravitational Universal Constant

R = Distance /Radius

PART A) As half its initial value is u'=2u, then

U = -\frac{2Gm^2}{R}

dU = -\frac{2Gm^2}{R}

dKE = -dU

Therefore replacing we have that,

\frac{1}{2}mv^2 =\frac{Gm^2}{2R}

Re-arrange to find v,

v= \sqrt{\frac{Gm}{R}}

v = \sqrt{\frac{6.67*10^{-11}*1*10^{28}}{1*10^{12}}}

v = 816.7m/s

Therefore the  velocity when the separation has decreased to one-half its initial value is 816m/s

PART B) With a final separation distance of 2r, we have that

2r = 2*10^3m

Therefore

dU = Gm^2(\frac{1}{R}-\frac{1}{2r})

v = \sqrt{Gm(\frac{1}{2r}-\frac{1}{R})}

v = \sqrt{6.67*10^{-11}*10^{28}(\frac{1}{2*10^3}-\frac{1}{10^{12}})}

v = 1.83*10^7m/s

Therefore the velocity when they are about to collide is 1.83*10^7m/s

7 0
4 years ago
Which statement best explains the relationship between the electric force between two charged objects and the distance between t
Thepotemich [5.8K]

Answer: a

Explanation:

8 0
3 years ago
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