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3 years ago

Find the momentum of a particl with a mass of one gram moving with half the speed of light.

Physics

1 answer:

joja [24]3 years ago

6 0

Answer:

129900

Explanation:

Given that

Mass of the particle, m = 1 g = 1*10^-3 kg

Speed of the particle, u = ½c

Speed of light, c = 3*10^8

To solve this, we will use the formula

p = ymu, where

y = √[1 - (u²/c²)]

Let's solve for y, first. We have

y = √[1 - (1.5*10^8²/3*10^8²)]

y = √(1 - ½²)

y = √(1 - ¼)

y = √0.75

y = 0.8660, using our newly gotten y, we use it to solve the final equation

p = ymu

p = 0.866 * 1*10^-3 * 1.5*10^8

p = 129900 kgm/s

thus, we have found that the momentum of the particle is 129900 kgm/s

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I need help understanding this concept . Would appreciate it so much. Thank you

Firlakuza [10]

Answer:

Explanation:

Both these questions are based on the Universal Law of Gravitation, which is given by :

F = Gm1m2 / r²

2) F = 6.67 x 10⁻¹¹ x 8 x 10³ x 1.5 x 10³ / 1.5 x 1.5

F = 6.67 x 10⁻⁵ x 8 / 1.5

F = 35.57 x 10⁻⁵ N

3) F = 6.67 x 10⁻¹¹ x 7.5 x 10⁵ x 9.2 x 10⁷ / 7.29 x 10⁴

F = 6.67 x 10⁻³ x 7.5 x 9.2 / 7.29

F = 63.13 x 10⁻³ N

7 0

3 years ago

A wire is used as a heating element that has a resistance that is fairly independent of its temperature within its operating ran

dedylja [7]

Answer:

Double the current

Explanation:

The energy delivered by the heater is related to the current by the following relation:

E= $I^{2}R t$

let R * t = k ( ∴ R and t both are constant)

so E= k $I^{2}$

Now let:

E2= k I₂^2

E2= 4E

⇒ k I₂^2= 4* k $I^{2}$

Cancel same terms on both sides.

I₂^2= 4* $I^{2}$

taking square-root on both sides.

√I₂^2 = √4* I^2

⇒I₂= 2I

If we double the current the energy delivered each minute be 4E.

3 0

3 years ago

When you break a magnet in half how many poles does each piece have.

Anastaziya [24]

It will have two poles

7 0

3 years ago

5. A single slit illuminated with a 500 nm light gives a diffraction pattern on a far screen. The 5th minimum occurs at 7.00° aw

abruzzese [7]

For a single slit illuminated with a 500 nm light gives a diffraction pattern on a far screen,the angle is mathematically given as

theta=25.3

Option A is correct

<h3> What angle does the 18th minimum occur?</h3>

Generally, the equation for the the angle is mathematically given as

$\theta=n(\lambda/d)$

Therefore

$\theta 1/ \theta 2=n1(\lambda/d)/ n2(\lambda/d)$

In conclusion

theta/7=16/5

theta=10*7/5

theta=25.3