All categories

3 years ago

Describe Thomson's concept of the atom?

2 answers:

5 0

Thomson atomic model was proposed by J.J Thomson in the year 1904 just after the discovery of electrons. According to the postulates of Thomson’s atomic model, an atom resembles a sphere of positive charge with electrons present inside the sphere. The positive and negative charge is equal and therefore an atom is electrically neutral. Thomson’s atomic model was compared to a spherical plum pudding as well as a watermelon. It was compared to a plum pudding because the electrons in the model look like the dry fruits embedded in a sphere of positive charge just like a spherical plum pudding. The model has also been compared to a watermelon because the red edible part of a watermelon was compared to the sphere having a positive charge and the black seeds filling the watermelon looked similar to the electrons inside the sphere.

lora16 [44]3 years ago

4 0

In Thomson's model, the atom is composed of electrons surrounded by a soup of positive charge to balance the electrons' negative charges, like negatively charged "plums" surrounded by positively charged "pudding". The 1904 Thomson modelwas disproved by Hans Geiger's and Ernest Marsden's 1909 gold foil experiment.

You might be interested in

Which resonance form is likely to contribute most to the correct structure of n2o?

Debora [2.8K]

Answer:

Explanation:

- The atoms combine to form molecules and attain stability by completing their octet. The formation of compound can take place either by transfer of electron from one atom to other or by sharing of electrons between them.

- Resonance structure of a molecule is of two or more forms in which the distribution of electrons around the structure is different but the chemical connectivity is same.

- The total number of valence electrons VE in (N N O) is :

VE = 2(5) + 6 = 16 electrons.

- Among the molecule, the electrons are distributed in atom in such a way that formation of triple bond will take place between two nitrogen atoms and a single bond will form between nitrogen and oxygen atom.

- The formal charge FC on each atom is determined as:

FC = VE - NBE - BE/2

Where,

NBE: Non-Bonding Electrons

BE : Bonding Electrons.

- The formal charge on each atom is: the nitrogen atom in center will possess 1+ formal charge and oxygen will possess 1- charge (oxygen is electronegative atom). Thus, results in formation of neutral molecule.

- The structure of (N N O) is shown in attachment.

- The resonance form which is likely to contribute most to the correct structure of (N_2 O) is:

- Structure for (N N O) showing one lone-pair of electrons on the terminal nitrogen atom, a triple bond between the two nitrogen atoms, a single bond between nitrogen and oxygen, and three lone-pairs of electrons on the terminal oxygen atom.

3 0

3 years ago

Who watching all star draft? Luka better get picked first ong

Whitepunk [10]

Na dame Dolla fo surrrreeeeee

5 0

3 years ago

Read 2 more answers

Which one will it be

liq [111]

Answer:

none

Explanation:

it's to high up to be affected by the gravity

3 0

3 years ago

Read 2 more answers

Which statement about the reaction is correct?

balu736 [363]

Answer:

I think D am not pretty show

8 0

3 years ago

A ball has a mass of 1.5kg and is thrown straight up with a speed of 60m/s, what is the ball’s momentum:

madam [21]

Answer:

Assumption: the air resistance on this ball is negligible. Take $g = 10\; \rm m \cdot s^{-2}$ .

a. The momentum of the ball would be approximately $60\;\rm kg \cdot m \cdot s^{-1}$ two seconds after it is tossed into the air.

b. The momentum of the ball would be approximately $\rm \left(-45\; \rm kg \cdot m \cdot s^{-1}\right)$ three seconds after it reaches the highest point (assuming that it didn't hit the ground.) This momentum is smaller than zero because it points downwards.

Explanation:

The momentum $p$ of an object is equal its mass $m$ times its velocity $v$ . That is: $\vec{p} = m \cdot \vec{v}$ .

Assume that the air resistance on this ball is negligible. If that's the case, then the ball would accelerate downwards towards the ground at a constant $g \approx -10\; \rm m \cdot s^{-2}$ . In other words, its velocity would become approximately $10\; \rm m \cdot s^{-1}$ more negative every second.

The initial velocity of the ball is $60\; \rm m \cdot s^{-1}$ . After two seconds, its velocity would have become $60\;\rm m \cdot s^{-1} + 2\; \rm s \times \left(-10\;\rm m \cdot s^{-1}\right) = 40\; \rm m \cdot s^{-1}$ . The momentum of the ball at that time would be around $p = m \cdot v \approx 60\; \rm kg \cdot m \cdot s^{-1}$ .

When the ball is at the highest point of its trajectory, the velocity of the ball would be zero. However, the ball would continue to accelerate downwards towards the ground at a constant $g \approx -10\; \rm m \cdot s^{-2}$ . That's how the ball's velocity becomes negative.

After three more seconds, the velocity of the ball would be $0\; \rm m \cdot s^{-1} + 3\; \rm s \times \left(-10\; \rm m \cdot s^{-2}\right) = -30 \; \rm m \cdot s^{-1}$ . Accordingly, the ball's momentum at that moment would be $p = m \cdot v \approx \left(-45\; \rm kg \cdot m \cdot s^{-1}\right)$ .

3 0

3 years ago