What do solids maintain thier shape where a fluids do not? does anybody know the answer

2 answers:

8 0

Solids maintain their shape, whereas fluids do not because the molecules in solids maintain a regular pattern and only vibrate, or move very slowly

Zolol [24]3 years ago

7 0

Hello!

Question - What do solids maintain thier shape where a fluids do not?

Answer - The reason solids can maintain there shape is because the fact that the molecules in a solid are moving very, very slowly other than water which the molecules are moving really fast, which makes the water unstable to keep its form.

Hope This Helps!

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Which of the following might be included in a chemical

azamat

Answer:

I think it's D

Explanation:

5 0

2 years ago

Americium-241 is used in some smoke detectors. It is an alpha emitter with a half-life of 432 years. How long will it take in ye

Mariulka [41]

Answer:

319 years

Explanation:

For a radioactive decay we have

N = N₀e^-kt , where:

N= Particles Remainng after a time t

N₀ = Particles Initially present

k = ln 2/ t₁/₂ , t₁/₂ is the half life of the radioactive element (Am-241)

We are given that the half-life is 432 yrs, from this inhformation we can calculate the value of k which then will be used to calculate the time Am-241 will take to decay to 40% once we realize we are given the ratio N/N₀.

k = ln 2/ 432 yr = 0.693/ 432 yr = 1.6 x 10⁻³ /yr

N/N₀ = e^-kt

N/N₀ = 60 (amount remaining after 40 % has decayed)/100

N/N₀ = 0.60

0.60 = e-^-kt

taking natural log to both sides of the equation to get rid of e:

ln (0.60) = -1.6 x 10⁻³ /yr x t ∴ t = - ln (0.60) /1.6 x 10⁻³/ yr

t = 0.51 /1.6 x 10⁻³ yr = 319 yrs

To verify our answer realize that what is being asked is how many years it will take to decay 40 %, and we are told the half life , 50 % decay , is 432 years, so for 40 % we will expect it will take less than that which agrees with our resul of 319 years.

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3 years ago

Calculate the energy for the transition of an electron from the n = 2 level to the n = 5 level of a hydrogen atom.

katovenus [111]

The energy for the transition:

The energy for the transfer of an electron from the n=2 level to the n=5 level of a hydrogen atom is 4.57 x $10^{-19}$ J

Calculation:

We are aware of the energy levels as n=2 and n=5. So, we may determine the wavelength of the photon released by the electron during this transition using Rydberg's equation:

1/λ = R x (1/ $n^{2}$ $_{final}$ - 1/ $n^{2} _{initial}$ )