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3 years ago

A turntable reaches an angular speed of "45 rev/min" in "4.10 s" after being turned on. What is its angular acceleration?

Physics

1 answer:

Marina86 [1]3 years ago

3 0

Answer:

1.15 rad/s²

Explanation:

given,

angular speed of turntable = 45 rpm

= $45\times \dfrac{2\pi}{60}$

= $4.71\ rad/s$

time, t = 4.10 s

initial angular speed = 0 rad/s

angular acceleration.

$\alpha = \dfrac{\omega_f-\omega_0}{t}$

$\alpha = \dfrac{4.71-0}{4.10}$

$\alpha = 1.15\ rad/s^2$

Hence, the angular acceleration of the turntable is 1.15 rad/s²

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2 years ago

Read 2 more answers

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SashulF [63]

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Put the value into the formula

$B=10^{-7}\times5.40\times\dfrac{(0.5\times10^{-3})\times(-0.730)i+(0.390)k}{(0.827)^3}$

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$\vec{dl}\times\vec{r}=(0.5\times10^{-3})\times(-0.730)i+(0.390)k$

$\vec{dl}\times\vec{r}=i(0.350\times0.5\times10^{-3}-0)+k(0+0.730\times0.5\times10^{-3})$

$\vec{dl}\times\vec{r}=0.000175i+0.000365k$

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$B=1.670\times10^{-10}i+3.484\times10^{-10}k$

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2 years ago

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