3LiOH+Fe(NO3)3--›Fe(OH)3↓+3LiNO3
n(LiOH)=m/M=(25g)/(24g/mol)=1,0417mol
n(Fe(OH)3)=1/3n(LiOH)=0,3472mol
m(Fe(OH)3)=n*M=0,3472mol*107g/mol=37,15g
Answer:sulfer by itself is not pleasant and it can be dangerous by itself but in large amounts.
Explanation:
Molar mass KBr = 119 g/mol
Volume in liters: 250.0mL / 1000 => 0.25 L
n = M x V
n = 1.20 x 0,25 => 0.3 moles of KBr
Therefore:
1 mole KBr ----------- 119 g
0.3 moles KBr -------- ??
0.3 x 119 / 1 => 35.7 g of KBr
If we are talking about a lower concentration of solutes then the term would be Hypotonic solution.
It’s the second won the air layer one
