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DIA [1.3K]
3 years ago
12

What is the tangential speed of a point on a wheel of a car if the point is located 0.114 m from the axis of rotation; and the w

heel is rotating at 6.53 rev/sec?
Physics
1 answer:
Svetach [21]3 years ago
3 0

Answer:

Tangential speed = R * w  where w is the angular speed

For a wheel   v = .114 m * 6.53 / sec = .744 m/s

Note that this is the tangential speed - If the wheel were moving at speed V then as viewed from the ground you have

top V + v

bottom   V - v

That is the wheel also has speed due to the speed of the axle (axis of rotation)

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A car initially traveling 7 m/s speeds up uniformly at a rate of 3 m/s2 until it reaches a velocity of 22 m/s. How much time did
dezoksy [38]

Answer:

t = 5 s

Explanation:

Data:

  • Initial Velocity (Vo) = 7 m/s
  • Acceleration (a) = 3 m/s²
  • Final Velocity (Vf) = 22 m/s
  • Time (t) = ?

Use formula:

  • \boxed{t=\frac{Vf - Vo}{a}}

Replace:

  • \boxed{t=\frac{22\frac{m}{s} -7\frac{m}{s}}{3\frac{m}{s^{2}}}}

Solve the subtraction of the numerator:

  • \boxed{t=\frac{15\frac{m}{s}}{3\frac{m}{s^{2}}}}

It divides:

  • \boxed{t=5\ s}

How much time did it take the car to reach this final velocity?

It took a time of <u>5 seconds.</u>

8 0
3 years ago
At the local hockey rink, a puck with a mass of 0.12kg is given an initial speed of 5.3m/s. If the coefficient of friction betwe
Salsk061 [2.6K]
Here’s my work to your question. I used Newton’s Second Law and a kinematics equation to arrive at the answer.

5 0
2 years ago
A car is running at a velocity of 50 miles/hour and the driver accelerates the car by 10miles/hour.How far the car travels from
dezoksy [38]
Initial velocity u = 50 miles/hour
acceleration a = 10 miles/hour
Time t = 2 hours
Distance travelled S = ut + (at^2)/2
Substituting the values in the second equation of motion,
S = 50*2 + (10 * 2 *2)/2
S = 100 + 20
S = 120 miles
Therefore the distance travelled by the car in the next two hours is 120 miles
4 0
3 years ago
Read 2 more answers
What affect does distance have on the force of gravity
DaniilM [7]

Answer:

the power of the gravitational force depends on the factors

mass and the distance

Explanation:

3 0
4 years ago
What is the force exerted on a charge of 2.5 µC moving perpendicular through a magnetic field of 3.0 × 102 T with a velocity of
OverLord2011 [107]

Given:

B = 3 \times 10^{2} T

V=5 \times 10^{3} \frac{m}{s}

q = 2.5 × 10^{-6} C

α = 90

To find:

Force = ?

Formula used:

Force on the moving charge is given by,

F = q V B sin α

Where F = force exerted on moving charge

V = velocity of charge

q = charge

α = angle between direction of V and B

Solution:

F = q V B sin α

Where F = force exerted on moving charge

V = velocity of charge

q = charge

α = angle between direction of V and B

F = 2.5 \times 10^{-6} \times 3 \times 10^{2}  \times 5 \times 10^{3}

F = 37.5 × 10^{-1}

F = 3.75 Newton

Thus, the force acting on the moving charge is 3.75 Newton.

8 0
3 years ago
Read 2 more answers
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