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Musya8 [376]
3 years ago
15

Which of the following is true?

Chemistry
1 answer:
Harlamova29_29 [7]3 years ago
5 0

Answer:

If we know that a reaction is an elementary reaction, then we know its rate law.

Explanation:

An elementary reaction is a reaction that takes place in one reactive encounter. This means that the two species interact in a single step to give the products.

If two reactants interact in a single step to yield the products then we can easily deduce the rate law from the reaction equation.

For instance, For the reaction;

2A + B → C

The rate law is

rate = k[A]²[B].

If the reaction is an elementary reaction and the equation of the reaction is balanced, then we can deduce the rate law from the balanced reaction equation.

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How many moles of gold atoms do 4.05×1024 gold atoms constitute?
VARVARA [1.3K]

Answer: There are 6.725 mols

Explanation:

Message me for extra information

parkguy786 snap

6 0
4 years ago
According to the equation below, how many moles of PbO are required to generate 3.88×1023 nitrogen molecules?
saul85 [17]

Answer:

1.935 mole

Explanation:

We'll begin by calculating the number of mole present in 3.88x10^23 molecules of nitrogen(N2). This can be obtained as follow:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 molecules. Therefore 1 mole of N2 contains 6.02x10^23 molecules.

Now if 1 mole of N2 contains 6.02x10^23 molecules,

Then Xmol of N2 will contain 3.88x10^23 molecules i.e

Xmol of N2 = (3.88x10^23)/6.02x10^23

Xmol of N2 = 0.645 mole

Now, we can obtain the number of moles of PbO required to generate 3.88x10^23 molecules (i.e 0.645 mole) of N2. This is illustrated below:

The equation for the reaction is given below:

3PbO + 2NH3 → 3Pb + N2 + 3H2O

From the balanced equation above, 3 moles of PbO produced 1 mole of N2.

Therefore, Xmol of PbO will produce 0.645 mole of N2 i.e

Xmol of PbO = 3 x 0.645

Xmol of PbO = 1.935 mole.

From the calculations made above,

1.935 mole of PbO will produce 3.88x10^23 molecules of nitrogen (N2).

8 0
4 years ago
What is the chemical equation
Serggg [28]

Chemical equation is the symbolic representation of chemical reactions.

Explanation

Chemical reactions are known as the reaction where two or more molecules or compounds react with each other leading to formation of product compounds along with either release or absorption of energy.

The symbolic representation of the processes occurring in a chemical reaction is termed as chemical equation.

The symbolic representation includes the reactants, products, external energy type and quantity of external energy and also about release of energy if occurs.

So the reactants are usually written in the left side of the chemical equation whereas on the right the products are written.

Both the sides are linked by a single headed arrow mark.

Some both the sides are linked by double heated arrow mark indicating the equilibrium chemical reaction.

5 0
3 years ago
How much 2.0 M phenylmagnesium chloride solution is needed if adding 2.9 mmol of Grignard reagent to a reaction? Your answer sho
Vladimir [108]

Answer:

1,45 mL

Explanation:

The Grignard reaction is a very important organometallic chemical reaction where the Grignard reagent ( alkyl, vinyl, or aryl-magnesium halides) acts as nucleophile in order to the formation of Carbon-Carbon bonds.

In the problem, the phenylmagnesium chloride is the grignard reagent. The volume of 2.0 M phenylmagnesium chloride solution you need to add 2.9 mmol is:

2,9 mmol × \frac{1mL}{2,0mM} = <em>1,45 mL</em>

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I hope it helps!

3 0
3 years ago
Heat is transferred by conduction through a wall of thickness 0.87 m. What is the rate of heat transfer if the walls thermal con
erik [133]

Explanation:

The given data is as follows.

         Thickness (dx) = 0.87 m,       thermal conductivity (k) = 13 W/m-K

        Surface area (A) = 5 m^{2},       T_{1} = 14^{o}C

        T_{2} = 93^{o}C

According to Fourier's law,

                    Q = -kA \frac{dT}{dx}

Hence, putting the given values into the above formula as follows.

                      Q = -kA \frac{dT}{dx}

                          = -13 W/m-k \times 5 m^{2} \times \frac{(14 - 93)}{0.87 m}

                          = 5902.298 W

Therefore, we can conclude that the rate of heat transfer is 5902.298 W.

4 0
3 years ago
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