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Musya8 [376]
2 years ago
15

Which of the following is true?

Chemistry
1 answer:
Harlamova29_29 [7]2 years ago
5 0

Answer:

If we know that a reaction is an elementary reaction, then we know its rate law.

Explanation:

An elementary reaction is a reaction that takes place in one reactive encounter. This means that the two species interact in a single step to give the products.

If two reactants interact in a single step to yield the products then we can easily deduce the rate law from the reaction equation.

For instance, For the reaction;

2A + B → C

The rate law is

rate = k[A]²[B].

If the reaction is an elementary reaction and the equation of the reaction is balanced, then we can deduce the rate law from the balanced reaction equation.

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7 0
2 years ago
A 3.301 mass % aqueous solution of potassium hydroxide has a density of 1.05 g/mL. Calculate the molality of the solution. Give
8_murik_8 [283]

<u>Answer:</u> The molality of potassium hydroxide solution is 0.608 m

<u>Explanation:</u>

We are given:

3.301 mass % of potassium hydroxide solution.

This means that 3.301 grams of potassium hydroxide is present in 100 grams of solution

Mass of solvent = Mass of solution - Mass of solute (KOH)

Mass of solvent = (100 - 3.301) g = 96.699 g

To calculate the molality of solution, we use the equation:

\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams})}

Where,

m_{solute} = Given mass of solute (KOH) = 3.301 g

M_{solute} = Molar mass of solute (KOH) = 56.1 g/mol

W_{solvent} = Mass of solvent = 96.699 g

Putting values in above equation, we get:

\text{Molality of KOH}=\frac{3.301\times 1000}{56.1\times 96.699}\\\\\text{Molality of KOH}=0.608m

Hence, the molality of potassium hydroxide solution is 0.608 m

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3 years ago
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C. Principal !!!!!!!!!


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