1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
rusak2 [61]
3 years ago
13

Look at the resistor illustrated in the figure above. Based on your knowledge of the resistor color code, what are the resistanc

e value and tolerance of this resistor?
A. 92 k 20%
B. 7.9 k 10%
C. 63 k 5%
D. 124 k 5%

Physics
2 answers:
vichka [17]3 years ago
6 0
A because of the resistors are four in this options first option is multiplied by 4
Fudgin [204]3 years ago
5 0

Answer:

In the given resistor we have a case of four bands

So, the first color will give first digit

Second color will give second digit

Third color will give the multiplier

And fourth digit will give the tolerance value

So, in the four colors

Blue color correspond to digit 6

Orange color correspond to digit 3

Orange color in case of multiplier  corresponds to 10^3

And Gold corresponds to tolerance value 5%

So, finally we will get

63k5%   since, 10^3=1000=kilos \text{that is k}

Therefore, option C is correct


You might be interested in
which religious group did not expand their membership by great numbers during the Second Great Awakening
Dimas [21]

Answer:

The Catholics.

Explanation:

see answer.

4 0
2 years ago
A viscous fluid is flowing through two horizontal pipes. They have the same length, although the radius of one pipe is three tim
Rudik [331]

The conservation of the mass of fluid through two sections (be they A1 and A2) of a conduit (pipe) or current tube establishes that the mass that enters is equal to the mass that exits. Mathematically the input flow must be the same as the output flow,

Q_1 = Q_2

The definition of flow is given by

Q =VA

Where

V = Velocity

A = Area

The units of the flow of flow are cubic meters per second, that is to say that if there is a continuity, the volume of input must be the same as that of output, what changes if the sections are modified are the proportions of speed.

In this way

Q_A = Q_B

Q_B = 2.94*10^2 m^3/s

7 0
3 years ago
lanet R47A is a spherical planet where the gravitational acceleration on the surface is 3.45 m/s2. A satellite orbitsPlanet R47A
qaws [65]

2.6×10^6\:\text{m}

Explanation:

The acceleration due to gravity g is defined as

g = G\dfrac{M}{R^2}

and solving for R, we find that

R = \sqrt{\dfrac{GM}{g}}\:\:\:\:\:\:\:(1)

We need the mass M of the planet first and we can do that by noting that the centripetal acceleration F_c experienced by the satellite is equal to the gravitational force F_G or

F_c = F_G \Rightarrow m\dfrac{v^2}{r} = G\dfrac{mM}{r^2}\:\:\:\:\:(2)

The orbital velocity <em>v</em> is the velocity of the satellite around the planet defined as

v = \dfrac{2\pi r}{T}

where <em>r</em><em> </em>is the radius of the satellite's orbit in meters and <em>T</em> is the period or the time it takes for the satellite to circle the planet in seconds. We can then rewrite Eqn(2) as

\dfrac{4\pi^2 r}{T^2} = G\dfrac{M}{r^2}

Solving for <em>M</em>, we get

M = \dfrac{4\pi^2 r^3}{GT^2}

Putting this expression back into Eqn(1), we get

R = \sqrt{\dfrac{G}{g}\left(\dfrac{4\pi^2 r^3}{GT^2}\right)}

\:\:\:\:=\dfrac{2\pi}{T}\sqrt{\dfrac{r^3}{g}}

\:\:\:\:=\dfrac{2\pi}{(1.44×10^4\:\text{s})}\sqrt{\dfrac{(5×10^6\:\text{m})^3}{(3.45\:\text{m/s}^2)}}

\:\:\:\:= 2.6×10^6\:\text{m}

5 0
3 years ago
Star A and Star B have measured stellar parallax of 1.0 arc second and 0.75 arc second, respectively. Which star is closer? How
zhuklara [117]

Answer:

Star A is closer than Star B

Explanation:

As we know that in parallax method of distance measurement the angle subtended by the star when it covers a distance of one Parsec arc length, it is known as parallax angle

Here we can say

angle = \frac{1 Parsec}{distance}

so we have

distance = \frac{1 Parsec}{angle}

so here we have

angle subtended by Star A = 1 arc sec

angle subtended by star B = 0.75 arc sec

now we have

distance for star A is given as

d_a = \frac{1 Parsec}{1} = 1 Parsec

distance of star B is given as

d_b = \frac{1 Parsec}{0.75} = 1.33 Parsec

So star A is closer than star B

7 0
3 years ago
Calculate the acceleration of a 270000-kg jumbo jet just before takeoff when the thrust on the aircraft is 160000 N .
Radda [10]

Answer:

<h3>The answer is 0.59 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{160000}{270000}  =  \frac{16}{27}  \\  = 0.592592...

We have the final answer as

<h3>0.59 m/s²</h3>

Hope this helps you

7 0
3 years ago
Other questions:
  • Alanna spots a bird in her back yard. The bird is sitting on a tree. Explain how the outer coverings of the bird and tree are di
    11·1 answer
  • Which condition will cause the pressure exerted by a gas in a closed container to increase?
    13·1 answer
  • The surface tension of water was determuned in a laboratory by using the drop weight method. 100 drops were released from a bure
    10·1 answer
  • An airplane on a runway accelerates at 4.0 meters/second2 for 28.0 seconds before takeoff. How far does the plane travel on the
    7·2 answers
  • At a pressure of one billionth (10–9) of atmospheric pressure, there are about 2.7 × 1010 molecules in one cubic centimeter of a
    6·1 answer
  • Does a compressed spring transfer elastic energy to its surroundings?
    12·1 answer
  • What is nylon?<br>answer​
    13·2 answers
  • Diffraction of light is the __________ of light as it passes through the Edges of a barrier or a slit.
    11·1 answer
  • Can an eagle reach exosphere through flying?
    15·2 answers
  • A 4.0-kg object has 72 J of kinetic energy.<br> Determine its speed.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!