Answer:
a)If concentration of [Sucrose] is changed to 2.5 M than rate will be increased by the factor of 2.5.
b)If concentration of [Sucrose] is changed to 0.5 M than rate will be increased by the factor of 0.5.
c)If concentration of
is changed to 0.0001 M than rate will be increased by the factor of 0.01.
d) If concentration when [sucrose] and
both are changed to 0.1 M than rate will be increased by the factor of 1.
Explanation:
Sucrose +
fructose+ glucose
The rate law of the reaction is given as:
![R=k[H^+][sucrose]](https://tex.z-dn.net/?f=R%3Dk%5BH%5E%2B%5D%5Bsucrose%5D)
![[H^+]=0.01M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0.01M)
[sucrose]= 1.0 M
..[1]
a)
The rate of the reaction when [Sucrose] is changed to 2.5 M = R'
..[2]
[2] ÷ [1]
![\frac{R'}{R}=\frac{[0.01 M][2.5 M]}{k[0.01M][1.0 M]}](https://tex.z-dn.net/?f=%5Cfrac%7BR%27%7D%7BR%7D%3D%5Cfrac%7B%5B0.01%20M%5D%5B2.5%20M%5D%7D%7Bk%5B0.01M%5D%5B1.0%20M%5D%7D)
![R'=2.5\times R](https://tex.z-dn.net/?f=R%27%3D2.5%5Ctimes%20R)
If concentration of [Sucrose] is changed to 2.5 M than rate will be increased by the factor of 2.5.
b)
The rate of the reaction when [Sucrose] is changed to 0.5 M = R'
..[2]
[2] ÷ [1]
![\frac{R'}{R}=\frac{[0.01 M][0.5 M]}{k[0.01M][1.0 M]}](https://tex.z-dn.net/?f=%5Cfrac%7BR%27%7D%7BR%7D%3D%5Cfrac%7B%5B0.01%20M%5D%5B0.5%20M%5D%7D%7Bk%5B0.01M%5D%5B1.0%20M%5D%7D)
![R'=2.5\times R](https://tex.z-dn.net/?f=R%27%3D2.5%5Ctimes%20R)
If concentration of [Sucrose] is changed to 0.5 M than rate will be increased by the factor of 0.5.
c)
The rate of the reaction when
is changed to 0.001 M = R'
..[2]
[2] ÷ [1]
![\frac{R'}{R}=\frac{[0.0001 M][1.0M]}{k[0.01M][1.0 M]}](https://tex.z-dn.net/?f=%5Cfrac%7BR%27%7D%7BR%7D%3D%5Cfrac%7B%5B0.0001%20M%5D%5B1.0M%5D%7D%7Bk%5B0.01M%5D%5B1.0%20M%5D%7D)
![R'=0.01\times R](https://tex.z-dn.net/?f=R%27%3D0.01%5Ctimes%20R)
If concentration of
is changed to 0.0001 M than rate will be increased by the factor of 0.01.
d)
The rate of the reaction when [sucrose] and
both are changed to 0.1 M = R'
..[2]
[2] ÷ [1]
![\frac{R'}{R}=\frac{[0.1M][0.1M]}{k[0.01M][1.0 M]}](https://tex.z-dn.net/?f=%5Cfrac%7BR%27%7D%7BR%7D%3D%5Cfrac%7B%5B0.1M%5D%5B0.1M%5D%7D%7Bk%5B0.01M%5D%5B1.0%20M%5D%7D)
![R'=1\times R](https://tex.z-dn.net/?f=R%27%3D1%5Ctimes%20R)
If concentration when [sucrose] and
both are changed to 0.1 M than rate will be increased by the factor of 1.
The metal cationic (+) atom to nonmetal anionic (-) atom ratio in the compound formed between Potassium and Chlorine is 1:1.
<h3>What is a compound?</h3>
A compound is made up of two or more atoms that are chemically combined together. In this case, we have the atoms; Potassium and Chlorine.
The electronic configuration of the atoms is not shown here but the metal cationic (+) atom to nonmetal anionic (-) atom ratio in the compound formed between Potassium and Chlorine is 1:1.
Learn more about chemical compounds:
brainly.com/question/12166462
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Based on the mole ratio of the reaction, 30 moles of NO2 will be produced from 15 moles of oxygen.
<h3>What is mole ratio of a reaction?</h3>
The mole ratio of a reaction is the ratio in which moles of reactants combine with themselves to form moles of products.
The equation of the reaction is given below:
![2 NO (g) + O_2 (g) ---> 2 NO_2 (g)](https://tex.z-dn.net/?f=2%20NO%20%28g%29%20%2B%20O_2%20%28g%29%20---%3E%202%20NO_2%20%28g%29)
The mole ratio of NO2 to oxygen is 2 : 1
Molles of NO2 produced from 15 moles of O2 = 15 × 2 = 30 moles
Therefore, 30 moles of NO2 will be produced from 15 moles of oxygen.
Learn more about moles ratio at: brainly.com/question/19099163