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Sedbober [7]
3 years ago
11

If there is a loss of 5.63 x 10-7kg of mass in a nuclear reaction, how many Joules of energy would be released? Recall that c =

3x108 m/s.I
Chemistry
1 answer:
melamori03 [73]3 years ago
5 0
E = m c^2   

E is energy in joule, m is mass in Kg and c ....speed of light (as you mention)

Substituting your values in the equation

E =  ( 5.63 x 10-7kg ) (3*10?^8) ^2 = 5.067 *10 ^10 J  

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A 260.0 −mL buffer solution initially contains 2.5×10−2 M of HCHO2 and 2.5×10−2 M of NaCHO2
FinnZ [79.3K]

The mass of HCHO2 and NaCHO2 to be added to the buffer solution are 0.23g and 0.44g respectively

Data;

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  • conc. of HCHO2 = 2.5*10^-2M
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<h3>Mass of Reagent Added</h3>

To calculate the mass of reagent added,  let's start with HCHO2

The mass of HCHO2 to be added is the number of moles of HCHO2 multiplied by it's molar mass.

260*10^-^3 * 2.5*10^-^2 * 46 = 0.229 = 0.23g

The mass of NaCHO2 to be added in the buffer solution is

260*10^-^3*2.5*10^-^2*68 = 0.442 = 0.44g

The mass of HCHO2 and NaCHO2 to be added to the buffer solution are 0.23g and 0.44g respectively

Learn more about buffer solution here;

brainly.com/question/22390063

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