I believe the answer is C, n = 3, l = 3, m = 3. The magnetic quantum number, or
<span>ml</span>, can only take values that range from <span>−l</span> to <span>+l</span>, as you can see in the table above.
For option C), the angular momentum quantum number of equal to ++2<span>, which means that <span>ml</span> can have a maximum value of </span>+2<span>. Since it is given as having a value of </span>+3**, this set of quantum numbers is not a valid one.
The other three sets are valid and can correctly describe an electron.
Trick question: you just stated everything in the beakers.
1.True
2.False
3.B
4.A
5.True
Answer:
Explanation:
Which of the following elements would lose an electron easily?
In particular, cesium (Cs) can give up its valence electron more easily than can lithium (Li). In fact, for the alkali metals (the elements in Group 1), the ease of giving up an electron varies as follows: Cs > Rb > K > Na > Li with Cs the most likely, and Li the least likely, to lose an electron