Answer:
The power in this flow is 
Explanation:
Given that,
Distance = 221 m
Power output = 680 MW
Height =150 m
Average flow rate = 650 m³/s
Suppose we need to calculate the power in this flow in watt
We need to calculate the pressure
Using formula of pressure
Where, 
= density
h = height
g = acceleration due to gravity
Put the value into the formula
We need to calculate the power
Using formula of power
Put the value into the formula
Hence, The power in this flow is
When glass is rubbed with a dry cloth, the friction creates charged static electricity; this in turn attracts small non charged particles of dust. The simplest way to put it, the dry cloth creates a static charge that attracts non charged dust particles.
Answer:
Explanation:
given,
radius of curve = 166 m
angle of the banked road = 11°
mass of car = 736 Kg
speed of the curve = 81 km/h
= 81 x 0.278 = 22.52 m/s
normal force acting on the tires
on tire there will be two force acting on it
first one will be force acting due to weight and the other force acting on the tire is due to centripetal force.
Say we have a cylinder
that has a height of dx, we see that the cylinder has a volume of: <span>
<span>Vcylinder = πr^2*h = π(5)^2(dx) = 25π dx
Then, the weight of oil in this cylinder is:
Fcylinder = 50 * Vcylinder = (50)(25π dx) = 1250π dx.
Then, since the oil x feet from the top of the tank needs to
travel x feet to get the top, we have:
Wcylinder = Force x Distance = (1250π dx)(x) = 1250π x dx.
<span>Integrating from x1 to x2 ft gives the total work to be: (x1
= distance from top liquid level to ground level; x2 = distance from bottom
liquid level to ground level)</span>
<span>W = ∫ 1250π x dx
<span>W = 1250π ∫ x dx
W = 625π * (x2 – x1)</span></span></span></span>
<span>x2 = 14 ft + 15 ft = 29 ft</span>
x1 = 14 ft + 1 ft = 15
ft
<span>
W = 625π * (29^2 - 15^2)
<span>W = 385,000π ft-lbs
= 1,209,513.17 ft-lbs</span></span>
