1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gnesinka [82]
3 years ago
9

Using the symbol below/above determine the number of protons, neutrons, and electrons in the element.

Chemistry
1 answer:
malfutka [58]3 years ago
7 0
Hi,
The correct answer is C.
Protons= 50 (because the atomic number of Sn is 50) —> The atomic number always represent the number of protons

Neutrons= 68 (if you want to find the number of neutrons, you need to do: atomic mass (118 in this case) - your number of protons (50)

Electrons= 46 (50 - 4)

You might be interested in
Consider the following reaction at a high temperature. Br2(g) ⇆ 2Br(g) When 1.35 moles of Br2 are put in a 0.780−L flask, 3.60 p
UNO [17]

Answer : The equilibrium constant K_c for the reaction is, 0.1133

Explanation :

First we have to calculate the concentration of Br_2.

\text{Concentration of }Br_2=\frac{\text{Moles of }Br_2}{\text{Volume of solution}}

\text{Concentration of }Br_2=\frac{1.35moles}{0.780L}=1.731M

Now we have to calculate the dissociated concentration of Br_2.

The balanced equilibrium reaction is,

                              Br_2(g)\rightleftharpoons 2Br(aq)

Initial conc.         1.731 M      0

At eqm. conc.      (1.731-x)    (2x) M

As we are given,

The percent of dissociation of Br_2 = \alpha = 1.2 %

So, the dissociate concentration of Br_2 = C\alpha=1.731M\times \frac{1.2}{100}=0.2077M

The value of x = 0.2077 M

Now we have to calculate the concentration of Br_2\text{ and }Br at equilibrium.

Concentration of Br_2 = 1.731 - x  = 1.731 - 0.2077 = 1.5233 M

Concentration of Br = 2x = 2 × 0.2077 = 0.4154 M

Now we have to calculate the equilibrium constant for the reaction.

The expression of equilibrium constant for the reaction will be :

K_c=\frac{[Br]^2}{[Br_2]}

Now put all the values in this expression, we get :

K_c=\frac{(0.4154)^2}{1.5233}=0.1133

Therefore, the equilibrium constant K_c for the reaction is, 0.1133

7 0
3 years ago
9. A student wished to prepare ethylene gas by dehydration of ethanol at 140oC using sulfuric acid as the dehydrating agent. A l
Arte-miy333 [17]

We have that the the liquid is

  • C_2H_5OH (ethanol
  • And at a condition of H_2SO4 as catalyst and temp 170

From the question we are told

  • A student wished to prepare <em>ethylene </em>gas by <em>dehydration </em>of ethanol at 140oC using sulfuric acid as the <em>dehydrating </em>agent.
  • A low-boiling liquid was obtained instead of ethylene.
  • What was the liquid, and how might the reaction conditions be changed to give ethylene

<h3>Ethylene formation</h3>

Generally the equation is

2C_2H_5OH------CH3CH_2O-CH_2CH_3+H_20

Therefore

with ethanol at 140oC

The product is diethyl ethen

The reaction at 170 ethylene will give

C_2H_5OH-------CH_2=CH_2+H_2O( at a condition of H_2SO4 as catalyst and temp 170)

Therefore

The the liquid is

  • C_2H_5OH (ethanol

For more information on Ethylene visit

brainly.com/question/20117360

8 0
2 years ago
Suppose you will fill a glass with ice cubes. When the ice cubes melt, is the glass still full
goblinko [34]
No. It will not still be full. The reason being is because when it melts, it's almost the same thing as compacting things down into another object (container). Therefore, you will have some room left i the glass. Like, if your trashcan was over-flowing, and you push it down to compact it so you can add more trash. So when the ice melts, it will not be full.
7 0
3 years ago
In the investigation "Comparing the Effects of the Products of Cellular Respiration
Marianna [84]

The solution changed color because the substances are not neutral.

<h3>pH</h3>

Chemical substances have different concentrations of the hydrogen cation, called PH.

The higher the pH, the more basic the substance, and the lower the more acidic.

Bromothymol blue is a pH indicator that changes its color according to the pH of the substance, yellow for acid, blue for basic and green for neutral.

In the case of the reactions in question, we have the release of CO2 (acid) in combustion and in cellular respiration, changing the color of bromothymol blue to yellow.

Learn more about pH in: brainly.com/question/491373

3 0
2 years ago
An exciton is: A charged particle made of electrons A charged particle made of holes A neutral particle made of an electron and
Alex

Answer:

A neutral particle made of an electron and hole

Explanation:

Exciton

It is the combination of an electron and a hole ( hole refers to the vacancy of an electron ) . And , as both the electron and the hole have the same charge but the polarity is opposite , the combination will lead to a neutral compound , i.e. ,  Exciton have no charge and so neutral .

It is free to move in the nonmetallic crystal and since it charge less , it is difficult to detect it directly .

7 0
3 years ago
Other questions:
  • Select all of the following that are particles of atoms. protons neutrons electrons quarks Atoms are composed of particles calle
    13·2 answers
  • In Section 5.6, we learned that triple bonds are stronger and shorter than single bonds. For example, a C−CC−C single bond has a
    15·1 answer
  • A precipitate forms when mixing solutions of sodium fluoride (NaF) and lead II nitrate (Pb(NO3)2). Complete and balance the net
    13·1 answer
  • If a decrease in temperature accompanies a reaction, what occurred?
    8·1 answer
  • Question 2
    9·1 answer
  • Molecules that are too large to flow across the<br> membrane need help from what structures?
    15·2 answers
  • My last question its easy but i dont get it lol help plz
    15·2 answers
  • Match the Terms to their definition:
    13·2 answers
  • Which of the following statements accurately describes the structure of the atom?
    12·1 answer
  • Which molecule has five atoms per molecule?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!