Answer:
ionically bonded compound transfer its electrons while covalently bonded compound share their electrons. ionically bonded compounds are charged while covalently bonded compound are neutral
Answer:
8.55x10^22 molecules
Explanation:
From the question given, the following data were obtained:
Density = 1g/mL
Volume = 2.56mL
Mass =?
Density = Mass /volume
Mass = Density x volume
Mass = 1 x 2.56
Mass = 2.56g
Now let us convert this mass (i.e 2.56g) of water to mole
Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol
Mass of H2O = 2.56g
Number of mole of H2O=? Number of mole = Mass /Molar Mass
Number of mole of H2O = 2.56/18
Number of mole of H2O = 0.142mol
From Avogadro's hypothesis, 1mole of any substance contains 6.02x10^23 molecules. This means that 1mole of H2O contains 6.02x10^23 molecules.
Now if 1mole of H2O contains 6.02x10^23 molecules, then 0.142mol of H2O will contain = 0.142 x 6.02x10^23 = 8.55x10^22 molecules
You input potential (stored<span>) </span>energy<span> into the </span>rubber band<span> system when you </span>stretched<span> the</span>rubber band<span> back. Because it is an </span>elastic<span> system, this kind of potential </span>energy<span> is specifically </span>called elastic<span> potential </span>energy<span>. ... When the </span>rubber band<span> is released, the potential </span>energy<span> is quickly converted to kinetic (motion) </span>energy<span>.</span>
B, I would believe. There are 58, but B is the closest we can get.
<h2>
<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>:</u><u>-</u></h2>
<em>The female part is the pistil. The pistil usually is located in the center of the flower and is made up of three parts: the stigma, style, and ovary. The stigma is the sticky knob at the top of the pistil. It is attached to the long, tubelike structure called the style.</em>
<h3>
<em><u>H</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>I</u></em><em><u>t</u></em><em><u> </u></em><em><u>W</u></em><em><u>i</u></em><em><u>l</u></em><em><u>l</u></em><em><u> </u></em><em><u>H</u></em><em><u>e</u></em><em><u>l</u></em><em><u>p</u></em><em><u> </u></em><em><u>Y</u></em><em><u>o</u></em><em><u>u</u></em><em><u>!</u></em></h3>