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Mashcka [7]
3 years ago
11

Which phenomenon may explain why some people want to join a fraternity or sorority badly enough that they will endure weeks of h

umiliation and physical discomfort to gain membership?
Physics
1 answer:
Doss [256]3 years ago
5 0

Justification of effort

Explanation:

The phrase justification of effort will best explain why some people may want to join a fraternity or sorority badly thereby enduring weeks of humiliation and physical discomfort to gain membership.

  • Effort justification is attributed to the field of social psychology.
  • It involves a person ascribing a value to an outcome.
  • It is best seen as people trying to pay the sacrifice to achieve a particular goal in the end of the task.
  • The goal is join the sorority
  • The sacrifice is the humiliation and discomfort they endure.
  • In the end, they pay the price and attain their goal.

learn more:

Being justified brainly.com/question/10846941

#learnwithBrainly

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A house is 54.0 ft long and 48 ft wide, and has 8.0-ft-high ceilings. What is the volume of the interior of the house in cubic m
pshichka [43]

Explanation:

Length of house, l = 54 ft = 16.45 m

Breadth of house, b = 48 ft = 14.63 m

Height of house, h = 8 ft = 2.43 m

We need to find the volume of the interior of the house. The house is in the form of cuboid. The volume of cuboid is given by :

V=l\times b\times h

V=16.45\ m\times 14.63\ m\times 2.43\ m

V=584.81\ m^3

Since, 1\ m^3=1000000\ cm^3

or the volume of the interior of the house, V=5.84\times 10^8\ cm^3

Hence, this is the required solution.

7 0
3 years ago
An object has a mass of 120 kg on the moon what is the force of gravity acting on the object on the moon
LiRa [457]

Answer: i think it is An object has a mass of 120 kg on the Moon. The force of gravity acting on the object on the Moon is 196 N. Sol'n: force = mass * gravity; gravity on the moon is 1/6 that on the Earth = 9.807*(1/6)=1.6345; f = m*g; f = 120*1.6345 =196.14.

Explanation:

6 0
3 years ago
Read 2 more answers
Can someone please help me with this? I'm so confused
bagirrra123 [75]

At theheight where it starts, just before it's dropped, the ball has
some potential energy.  The higher that spot is, the more potential
energy the ball has.  After the drop, whenever the ball is lower than
the height from which it was dropped, it has less potential energy, and
the missing potential energy shows up as kinetic energy ... motion.

This is the whole idea of the roller coaster.  A machine drags it up to
the top of the first hill, giving it lots of potential energy.  After that, as
long as it doesn't try to rise higher than the first hill, it never runs out
of energy, and keeps going.

A). and B).
The ball keeps going forward until it rises again to the same height it
was dropped from ... on the other side.  Then it stops and falls back.

C). The ball can never rise higher than the height it was dropped from.
If the hump in the middle is the same height as the drop-height, then
the ball stops right there, and falls back.

D).  Same as B).  As long as the track inside the loop is never higher
than the droop-height, the ball just keeps going forward.

E). Same idea.  Here it looks like the drop-height is the same as the
top of the loop. The ball can't rise higher than it was dropped from,
so it gets as far as the top of the loop and stops there.  From there,
I think it drops straight down from the top of the loop, instead of
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3 0
4 years ago
A +15 nC point charge is placed on the x axis at x = 1.5 m, and a -20 nC charge is placed on the y axis at y = -2.0m. What is th
IceJOKER [234]

Answer:E=75\ N/m

Explanation:

Given

First charge of q_1=15\ nC is placed at x=1.5\ m

Second charge  q_2=-20\ nC is placed at y=-2\ m

Electric field is given by

E=\frac{kq}{r^2}

Electric field due to q_1 is away from it

E_1=\frac{9\times 10^9\times 15\times 10^{-9}}{(1.5)^2}

E_1=60\ N/m

Electric field due to q_2

E_2=\frac{9\times 10^9\times 20\times 10^{-9}}{2^2}

E_2=45\ N/m

Net electric field will be vector addition of two

\vec{E_{net}}=\vec{E_1}+\vec{E_2}

\vec{E_{net}}=-60\hat{i}-45\hat{j}

Magnitude of Electric field is

E=\sqrt{60^2+45^2}

E=75\ N/m

8 0
3 years ago
A 1.5m wire carries a 6 A current when a potential difference of 61 V is applied. What is the resistance of the wire?
Alisiya [41]

Resistance = (voltage) / (current)

For this piece of wire . . .

Resistance = (61 volts) / (6 Amperes)

Resistance = (61/6) (V/A)

<em>Resistance = (10 and 1/6) ohms</em>

Since you know the voltage and current, the length doesn't matter.

7 0
3 years ago
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