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yanalaym [24]
3 years ago
10

What stage do most stars spend the majority of their lives in?

Physics
2 answers:
Anna007 [38]3 years ago
8 0
It a stage known as the "Main Sequence" stage. Stars achieve nuclear stability at this point and remain in this stage until the end of their lives.
Have a nice day!

hjlf3 years ago
3 0
Out of the 7 most important stages a star spends about 90% of it's life in the "Main Sequence Star" stage. In this stage a star forms helium in it's core by fusing hydrogen atoms. Actually the Sun is in this stage right now. How long it stays in this stage depends on the star's size.
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Answer:

Only 2,3,4 are true

Explanation:

Bosons Particles are particles that condense to the same state. Bosons particle have integral spin like 0 , $\hbar$, 2$\hbar, 3$\hbar$, etc. Bosons particles always have asymmetric wave function and there is exchange of particles.

1) It does not obey Fermi_ Dirac statistics

2) It obeys Bose-Einstein statistics

3) The object can have intrinsic spin 2$\hbar

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5) No Bosons particle are symmetric and not asymmetric

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What is the final step in the fourth stage of technological design
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after a product has been improved and approved? reporting the results finding ways to lower costs selling a prototype determining criteria.

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The bungee cord has an unstretched length of 20.0 m. The mass of the student is 50.0 kg. The gravitational field strength is 9.8
viva [34]

Answer:

a) g.p.e.=mass × gravitational field strength × height

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Is it true that if an object is moving it has kinetic energy
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Yes an object in motion has kinetic energy
5 0
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A fast moving vehicle travelling at a speed of 25.4 m/s comes up behind another vehicle which is
ale4655 [162]

Answer:

     a = 6.1 m / s²

Explanation:

For this kinematics exercise, to solve the exercise we must set a reference system, we place it in the initial position of the fastest vehicle

Let's find the relative initial velocity of the two vehicles

          v₀ = v₀₂ - v₀₁

          v₀ = 25.4 - 13.6

          v₀ = 11.8 m / s

 

the fastest vehicle

          x = v₀ t + ½ a t²

The faster vehicle has an initial speed relative to the slower vehicle, therefore it is as if the slower vehicle were stopped, so the distance that must be traveled in a fast vehicle to reach this position is

          x = 11.4 m

         

let's use the expression

           v² = v₀² - 2 a x

how the vehicle stops v = 0

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          a = 6.1 m / s²

this velocity is directed to the left

8 0
2 years ago
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