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yanalaym [24]
3 years ago
10

What stage do most stars spend the majority of their lives in?

Physics
2 answers:
Anna007 [38]3 years ago
8 0
It a stage known as the "Main Sequence" stage. Stars achieve nuclear stability at this point and remain in this stage until the end of their lives.
Have a nice day!

hjlf3 years ago
3 0
Out of the 7 most important stages a star spends about 90% of it's life in the "Main Sequence Star" stage. In this stage a star forms helium in it's core by fusing hydrogen atoms. Actually the Sun is in this stage right now. How long it stays in this stage depends on the star's size.
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In a redox reaction the substance that accepts electrons is said to be
netineya [11]
The question "<span>In a redox reaction the substance that accepts electrons is said to be?" is a bit vague. By definition, a "redox" or "reduction" reaction is one where classified by a gain of electrons. On the other hand, if it is a loss of electrons, then it is an oxidation reaction.</span>
8 0
3 years ago
Ice skaters often end their performances with spin turns, where they spin very fast about their center of mass with their arms f
nekit [7.7K]

Answer:

Her angular speed (in rev/s) when her arms and one leg open outward is 1.4 rev/s

Explanation:

given information:

moment inertia of arm and leg when in, I₁ = 0.9 kgm²

moment inertia of arm and leg when extended, I₂ = 2.9 kgm²

angular speed when in, ω₁ = 4.5 rev/s

so, her angular speed (in rev/s) when her arms and one leg open outward is

L₁ = L₂

I₁ω₁ = I₂ω₂

ω₂ = I₁ω₁/I₂

     = 0.9 x 4.5/2,9

     = 1.4 rev/s

4 0
3 years ago
An 805-kg race car can drive around an unbanked turn at a maximum speed of 54 m/s without slipping. the turn has a radius of cur
SIZIF [17.4K]
(a) Equating centripetal force to friction force, one finds the relation
  v² = kar
for car speed v, coefficient of friction k, radius of curvature r, and downward acceleration a.

There is already downward acceleration due to gravity. The additional accceleration due to the wing is
  a = F/m = 10600 N/(805 kg) ≈ 13.1677 m/s²
We presume this is added to the 9.80 m/s² gravity provides, so the coefficient of friction is
  k = v²/(ar) = (54 m/s)²/((13.1677 m/s² +9.80 m/s²)·(155 m))
  k ≈ 0.8191

(b) The maximum speed is proportional to the square root of the downward acceleration. Changing that by a factor of 9.80/(9.80+13.17) changes the maximum speed by the square root of this factor.
  max speed with no wing effect = (54 m/s)√(9.8/22.97) ≈ 35.27 m/s
8 0
3 years ago
Convert horsepower to Kilo Newton.
SVEN [57.7K]

1 horsepower is equivalent to 0.7457 Kilo Newton. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

8 0
3 years ago
2 Points
lana66690 [7]

Answer:

the answer will be 3.763 seconds

6 0
3 years ago
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