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yanalaym [24]
3 years ago
10

What stage do most stars spend the majority of their lives in?

Physics
2 answers:
Anna007 [38]3 years ago
8 0
It a stage known as the "Main Sequence" stage. Stars achieve nuclear stability at this point and remain in this stage until the end of their lives.
Have a nice day!

hjlf3 years ago
3 0
Out of the 7 most important stages a star spends about 90% of it's life in the "Main Sequence Star" stage. In this stage a star forms helium in it's core by fusing hydrogen atoms. Actually the Sun is in this stage right now. How long it stays in this stage depends on the star's size.
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A uniform linear charge of 2.0 nC/m is distributed along the x axis from x = 0 to x = 3 m. What is the x component of the electr
balu736 [363]

Answer:

The x component of the electric field at y=2m is E_{x}=17.97\frac{N}{C}

Explanation:

For a linear charge, using <u>Gauss Law</u>, we get that the <em>Electric field (radial) has the following form</em>

E=\frac{\lambda}{2\pi\epsilon_{0}r}

<em>where λ is the charge for longitud unit given in the problem, r is replaced by the y coordinate, and there are two known more data</em>. So

E=\frac{2*10x^{-9}}{2*2\pi\epsilon_{0}}=17.97\frac{N}{C}

is the x component of the Electric field at y=2m on the y axis, which is what we wanted to know.

4 0
3 years ago
The color produced by fireworks is all due to the chemicals inside of the firework itself. Which of these would describe a firew
AlexFokin [52]
Your answer is D- high energy and short wavelengths : )
3 0
4 years ago
Read 2 more answers
Coil the wire around the nail. Connect one end of the wire to the positive battery terminal. Connect the other end of the wire t
Ostrovityanka [42]

A).  No.  In fact, the longer you leave things hooked up like this, the weaker the battery becomes.

<em>B).  Yes !  </em>As long as everything stays hooked up like this, the nail is a magnet. (Until the battery finally dies of exhaustion.)

C).  No.

D).  I don't think so.  Never heard of this one.

5 0
4 years ago
The human body has an energy efficiency of
Kamila [148]
Protons and neutrons
8 0
4 years ago
Suppose we could shrink the Earth without changing its mass. At what fraction of its current radius would the free-fall accelera
spin [16.1K]

Answer:

R' = \frac{1}{\sqrt{3}}R

Explanation:

The acceleration due to gravity on the surface of the Earth is given by:

g=\frac{GM}{R^2}

where

G is the gravitational constant

M is the mass of the Earth

R is the radius of the Earth

Here we want to find the new Earth radius R' for which the gravitational acceleration at the surface, g', would be 3 times the current value of g:

g' = 3g

So we would have

\frac{GM}{R'^2}=3(\frac{GM}{R^2})

Solving the equation for R', we find

R'^2 = \frac{1}{3}R^2\\R' = \frac{1}{\sqrt{3}}R

7 0
3 years ago
Read 2 more answers
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