Si usted trata de contrabandear lingotes de oro llenando su mochila, cuyas dimensiones son de 56 cm * 28 cm * 22 cm, ¿cuál sería
1 answer:
Answer:
Mass, m = 665.77 kg
Explanation:
The question says that "If you try to smuggle gold bars by filling your backpack, whose dimensions are 56 cm * 28 cm * 22 cm, what would be its mass? "
The dimension of gold bar is 56 cm×28 cm×22 cm
We know that the density of gold is 19.3 g/cm³
The mas per unit volume of a material is called its density. It can be given by :
So, the mass of the gold bar is 665.77 kg.
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m = mass of the ice added = ?
M = mass of water = 1.90 kg
= specific heat of the water = 4186 J/(kg ⁰C)
= specific heat of the ice = 2000 J/(kg ⁰C)
= latent heat of fusion of ice to water = 3.35 x 10⁵ J/kg
= initial temperature of ice = 0 ⁰C
= initial temperature of water = 79 ⁰C
T = final equilibrium temperature = 8 ⁰C
using conservation of heat
Heat gained by ice = Heat lost by water
m (T -
) + m
= M
(
- T)
inserting the values
m (4186) (8 - 0) + m (3.35 x 10⁵ ) = (1.90) (4186) (79 - 8)
m = 1.53 kg