Calculate the mass of KHC8H4O4 that reacts with 20 ml of 0.1 Monday NaOH.

1 answer:

3 0

Obviously only one of the H's was replaced as the product showed one mole of water So the ratio is 1 to 1.Moles of NaOH used Molarity x volume = 0.1 x0.015(L) = 0.0015 moles
Mass of acid used is 0.0015 x 204 = 0.306g
moles MM

hopefully this helps

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