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san4es73 [151]
3 years ago
5

Trial and error learning is an example of

Chemistry
1 answer:
lbvjy [14]3 years ago
8 0

Answer:

A is your answer i believe

Explanation:

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If a material mixes readily with water it is identified as
Rama09 [41]
If a material mixes readily with water it is describe as HYDROPHILIC. Hydrophilic substances are water loving molecules, there reaction with water is favorable in term of thermodynamics. This type of substance are usually charged and often have ability to get involve in hydrogen bonding. 
3 0
3 years ago
A gate made of painted iron is beginning to rest in areas where the paint has worn away why is the formation of rust considered
Pavel [41]

Answer:

because it is two substances reacting together to create a new substance

Explanation:

when iron rusts, iron molecules react with the oxygen molecules creating iron oxide aka rust.

3 0
2 years ago
I was wondering what the answer for this question would be ?
mixer [17]

Answer:

C. H2O is the base and H3O+ is the conjugate acid

Explanation:

According to Bronsted-Lowry acid-base theory, an acid is a substance that loses an hydrogen ion or proton (H+) while a base is a substance that gains an hydrogen ion (H+) or proton. Furthermore, this theory states that, the molecule formed when an acid donates its proton is called the CONJUGATE BASE, while the molecule formed when the base accepts proton is called CONJUGATE ACID.

In this question, the following equation is given:

NH4+(aq) + H2O(aq) ⇌NH3(aq) + H3O+ (aq)

Water (H2O) is the base in this equation because according to Bronsted-Lowry acid-base theory, it accepts an hydrogen ion (H+) while hydroxonium ion (H3O+) is the conjugate acid.

7 0
3 years ago
For the following reaction, 4.21 grams of hydrogen gas are allowed to react with 10.6 grams of ethylene (C2H4) . hydrogen(g) + e
sergiy2304 [10]

Answer:a)  11.34 g of ethane (C_2H_6) can be formed

b) C_2H_4 is the limiting reagent

c) 3.44 g of the excess reagent remains after the reaction is complete

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}\times{\text{Molar Mass}}    

1. \text{Moles of} H_2=\frac{4.21}{2}=2.10moles

2. \text{Moles of} C_2H_4=\frac{10.6}{28}=0.378moles

H_2(g)+C_2H_4(g)\rightarrow C_2H_6(g)

According to stoichiometry :

1 mole of C_2H_4 require 1 mole of H_2

Thus 0.378 moles of C_2H_4 will require=\frac{1}{1}\times 0.378=0.378moles  of H_2

Thus C_2H_4 is the limiting reagent as it limits the formation of product and H_2 is the excess reagent.

moles of H_2 left = (2.10-0.378) = 1.72 moles

mass of H_2 left=moles\times {\text {Molar mass}}=1.72moles\times 2g/mol=3.44g

According to stoichiometry :

As 1 mole of C_2H_4 give = 1 mole of C_2H_6

Thus 0.378 moles of C_2H_4 give =\frac{1}{1}\times 0.378=0.378moles  of C_2H_6

Mass of C_2H_6=moles\times {\text {Molar mass}}=0.378moles\times 30g/mol=11.34g

Thus 11.34 g of ethane is formed.

4 0
3 years ago
why is it better to use several trials of a titration rather than one trial to determine the concentration of a solution of unkn
svlad2 [7]
Because you are never 100% precise during the work, so it's best and most accurate answer is always the average of more trials. basically the more you do, the more accurate the answer shall be 
6 0
3 years ago
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