The static frictional force between a 95-kilogram object and the floor is 45 Newtons. The kinetic frictional force is only 22 Ne
1 answer:
Answer:
F = 69.5 [N]
Explanation:
We must remember that the friction force is defined as the product of the normal force by the coefficient of friction, and it can be calculated by the following expression.
where:
N = normal force [N]
miu = friction coefficient
f = friction force = 22 [N]
Now we must calculate the force exerted by means of Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
where:
F = force exerted [N]
f = friction force [N]
m = mass = 95 [kg]
a = acceleration = 0.5 [m/s²]
Now replacing:
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Answer:
42.417 cm³
Explanation:
The formula to find the volume of a cone is :
V = × π r² h
Here,
r ⇒ radius ⇒ 3 cm
h ⇒ height ⇒ 4.5 cm
<u>Let us find it now.</u>
V = × π r² h
V = × π × 3 × 3 × 4.5
V = × π × 9 × 4.5
V = × π × 9 × 4.5
V = × π × 40.5
V = × 3.142 × 40.5
V = × 127.251
V = <u>42.417 cm³</u>