Answer:
Dogs are able to hear much higher frequencies than humans are capable of detecting. For this reason, dog whistles that are inaudible to the human ear can be heard easily by a dog. If a dog whistle has a frequency of 30,000 Hz, what is the wavelength of the sound emitted?
Answer:
The decrease of these factors increases the acceleration.
Explanation:
Hi, the decrease of these factors increases the acceleration.
Air resistance is a force opposing the acceleration. So if it decreases, the acceleration increases, because the opposite forces decreases.
The same is applied to the force of gravity, since the rocket travels upward; gravity is also an opposite force.
Finally, if the mass decreases, it means that the rocket becomes lighter and the force acting on the smaller mass causes an increase in the acceleration.
Answer:
In SI units 98.1 N, 16.24 N
English units 22.053861 lbf, 3.6509144 lbf
Explanation:
g = Acceleration due to gravity
m = Mass = 10 kg
Weight on Earth

Converting to lbf

On Moon

Converting to lbf

In SI units 98.1 N, 16.24 N
English units 22.053861 lbf, 3.6509144 lbf
Answer:
Force exerted, F = 1.5 N
Explanation:
It is given that, a boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s.
i.e. u = 0
v = 30 m/s
Time taken, t = 0.06 s
Mass of the paper, m = 0.003 kg
We need to find the force the boxer exert on it. The force can be calculated using second law of motion as :



F = 1.5 N
So, the force the boxer exert on the paper is 1.5 N. Hence, this is the required solution.
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