The answer is the last option "Respiration"
Hi there!
We can use the following kinematic equation:
vf = final velocity (? m/s)
vi = intial velocity (0 m/s)
a = acceleration (5 m/s²)
d = displacement (8 m)
Plug in the givens and solve.
Si la velocidad es 3 m/s, y ellos quieren saber la distancia despues 2 segundos, necesita que multiplicar 2 y 3.
La respeusta debiera ser 6m.
Answer:
H = Vy t - 1/2 g t^2 height of an object with an initial "vertical" velocity
at t sec after firing
Vy = 78 m/s * sin 40 = .643 * 78 m/s = 50.1 m/s
H = 50.1 * 6 - 1/2 * 9.8 * 6^2 = 300 m - 176 m = 124 m
Answer:
the formula is efficiency = output / input × 100%
