The angular speed such a cylinder must have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is 0.046 rad/s.
<h3>
Angular speed of the cylinder</h3>
The angular speed such a cylinder must have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is calculated as follows;
a = v²/r
v² = ar
(ωr)² = ar
ω²r² = ar
ω²r = a
ω² = a/r
ω = √(a/r)
where;
- a is centripetal acceleration = acceleration due to gravity, g
- r is radius of the cylinder = 5.66 m / 2 = 2.83 mi = 4554.4 m
- ω is angular speed
ω = √(g/r)
ω = √(9.8/4554.4)
ω = 0.046 rad/s
Thus, the angular speed such a cylinder must have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is 0.046 rad/s.
Learn more about angular speed here: brainly.com/question/6860269
#SPJ1
Answer:
a)
b)
Explanation:
By conservation of the linear momentum:
When the bullet is shot horizontally
When the bullet is shot at 56.0° above the horizontal,
Since on the y-axis ground will absorb the shock, we only make the calculations on the x-axis:
Answer:
force
Explanation:
If you need explanation lmk and if that's not the answer lmk as well so i can think of other one's hope it helps
Answer:
It's Option D
Explanation:
Red line bounces off left side of black line.
Y e s i t ' s c a l l e d " t h e e f f o r t f o r c e "
H o p e t h i s h e l p s
:) L O L