All categories

3 years ago

Please help, any and all is very much appreciated!

Chemistry

1 answer:

iogann1982 [59]3 years ago

3 0

1. True
2. False
3. False
4. True
5. True
6. True
7. All of the above
8. According to their reactivity with other substances
9. Standard temp and pressure
10. Flush your eyes in the eye flush for 15-20 minutes

You might be interested in

Petroleum is a mixture of hydrocarbons. It is separated into useful fractions by fractional distillation.

Hunter-Best [27]

Explanation:

Fractional distillation is used to separate crude oil into simpler, more useful mixtures . This method can be used because different hydrocarbons have different boiling points

Hope this help u

3 0

3 years ago

18. An objective observation is one without

elena55 [62]

D. details about what happening

5 0

3 years ago

Read 2 more answers

Excess aqueous copper(II) nitrate reacts with aqueous sodium sulfide to produce aqueous sodium nitrate and copper(II) sulfide as

nikitadnepr [17]

The question in incomplete, complete question is;

Determine the theoretical yield:

Excess aqueous copper(II) nitrate reacts with aqueous sodium sulfide to produce aqueous sodium nitrate and copper(II) sulfide as a precipitate. In this reaction 469 grams of copper(II) nitrate were combined with 156 grams of sodium sulfide to produce 272 grams of sodium nitrate.

Answer:

The theoretical yield of sodium nitrate is 340 grams.

Explanation:

$Cu(NO_3)_2(aq)+Na_2S(aq)\rightarrow 2NaNO_3(aq)+CuS(s)$

Moles of copper(II) nitrate = $\frac{469 g}{187.5 g/mol}=2.5013 mol$

Moles of sodium sulfide = $\frac{156 g}{78 g/mol}=2 mol$

According to reaction, 1 mole of copper (II) nitrate reacts with 1 mole of sodium sulfide.

Then 2 moles of sodium sulfide will react with:

$\frac{1}{1}\times 2mol= 2 mol$ of copper (II) nitrate

As we can see from this sodium sulfide is present in limiting amount, so the amount of sodium nitrate will depend upon moles of sodium sulfide.

According to reaction, 1 mole of sodium sulfide gives 2 mole of sodium nitrate, then 2 mole of sodium sulfide will give:

$\frac{2}{1}\times 2mol=4 mol$ sodium nitrate

Mass of 4 moles of sodium nitrate :

85 g/mol × 4 mol = 340 g

Theoretical yield of sodium nitrate = 340 g

The theoretical yield of sodium nitrate is 340 grams.

7 0

3 years ago

Read 2 more answers

Mr. Romeo wants to make a solution of NaOH. He measures out 97.68 grams and puts it into 3 liters

Studentka2010 [4]

Answer: Molarity of the solution is 0.813 M.

Explanation:

Given : Mass of NaOH = 97.68 g

Volume of solution = 3 L

The molar mass of NaOH is 39.99 g/mol. Hence, moles of NaOH are calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{97.68 g}{39.99 g/mol}\\= 2.44 mol$

Molarity is the number of moles of solute present in a liter of solution. Therefore, molarity of given solution is calculated as follows.

$Molarity = \frac{no. of moles of solute}{Volume (in L)}\\= \frac{2.44 mol}{3 L}\\= 0.813 M$

Thus, we can conclude that molarity of the solution is 0.813 M.

8 0

3 years ago

Question 2: Naming Hydrocarbons

oksian1 [2.3K]

Answer:

1) 1-Pentyne

2) But-2-yne

3) Ethyne

4) 1-Propyne

5) 1-Butyne

6) Pent-2-yne

Explanation:

1) The number of carbon on the longest chain = 5, (two carbon atoms between the triple bond) therefore the prefix is pen-

The functional group is the triple bond on the first carbon with the suffix -yne

The name of the compound is 1-Pentyne

2) There are 4 carbon atoms on the longest chain, therefore, the prefix is but-

The location of the triple bond functional group (suffix; -yne) is on the second carbon atom

Therefore, the name of the compound is But-2-yne

3) The triple bond functional group is between the only two carbon atoms, therefore, the name is Ethyne

4) The number of carbon atoms = 3, with a prefix prop-, and the functional group on the first carbon atom on the longest chain is the triple bond, with suffix -yne

Therefore, the name of the compound is 1-Propyne

5) The number of carbon atoms on the longest chain = 4, the prefix is but-

The location of the triple bond functional group (suffix -yne) is on the first carbon atom

Therefore, the name is 1-Butyne

6) The number of carbon atoms on the longest chain = 5, the prefix of the compound is pen-

The location of the triple bond functional group (suffix; -yne) is on the second carbon atom, therefore;

The name of the compound is Pent-2-yne

4 0

3 years ago