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3 years ago

2) Calculate the gravitational potential energy that a parachutist has just as he

Physics

1 answer:

masya89 [10]3 years ago

5 0

Answer:

<em>The gravitational potential energy of the parachutist is 3,528,000 J</em>

Explanation:

<u>Gravitational Potential Energy </u>

It's the energy stored in an object because of its height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where:

m = mass of the object

h = height with respect to a fixed reference

g = acceleration of gravity, usually taken as $9.8 m/s^2$ .

The parachutist has a mass of m=120 kg and he jumps at a height of h= 3,000 m. Computing the gravitational potential energy:

U = 120 * 3,000 * 9.8

U = 3,528,000 J

The gravitational potential energy of the parachutist is 3,528,000 J

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A 1-kilogram ball has 8 joules of kinetic energy.What is it speed?

scZoUnD [109]

K.E=0.5*mv²
v=square root 2ke/m
v= square root 2*8J/1 kg
v= 4 m/s

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2 years ago

The Andromeda Galaxy is faintly visible to the naked eye in the constellation Andromeda. Suppose instead it were located in the

Kaylis [27]

Answer:

a) We could not see it at all.

Explanation:

The most distant object that can be seen is the andromeda galaxy, which we may have a slight view of. The andromeda galaxy is a large galaxy that along with the previous two is also part of the local group. Spiral-type galaxy that is approximately 250,000 light years in diameter (more than twice the diameter of the Milky Way!) And is about 2.9 million light years away from our galaxy. Because of its distance, we have difficulty visualizing this galaxy, we would have this difficulty even if the andromeda galaxy was in the center of the Milky Way, but maintaining its current distance. That is, even if the andromeda galaxy were located in the same direction in space as the center of the Milky Way (but still at its current distance), we could not see it at all.

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3 years ago

A car is traveling at 120 km/h (75 mph). When applied the braking system can stop the car with a deceleration rate of 9.0 m/s2.

Bumek [7]

Answer:

the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15

Explanation:

Given that;

speed of car V = 120 km/h = 33.3333 m/s

Reaction time of an alert driver = 0.8 sec

Reaction time of an alert driver = 3 sec

extra time taken by sleepy driver over an alert driver = 3 - 0.8 = 2.2 sec

now, extra distance that car will travel in case of sleepy driver will be'

S_d = V × 2.2 sec

S_d = 33.3333 m/s × 2.2 sec

S_d = 73.3333 m

hence, number of car of additional car length n will be;

n = S_n / car length

n = 73.3333 m / 5m

n = 14.666 ≈ 15

Therefore, the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15

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3 years ago

The magnitude of the electrical force acting between a +2.4 x 10- C charge and a +1.8 x 10- C charge that are separated

Brrunno [24]

Answer: 6.07 N

Explanation:

According to Coulomb's Law:

$F_{E}= K\frac{q_{1}.q_{2}}{d^{2}}$

Where:

$F_{E}$ is the electrostatic force

$K=8.99(10)^{9} Nm^{2}/C^{2}$ is the Coulomb's constant

$q_{1}=2.4(10)^{-8} C$ and $q_{2}=1.8(10)^{-6} C$ are the electric charges

$d=0.008 m$ is the separation distance between the charges

Solving:

$F_{E}= 8.99(10)^{9} Nm^{2}/C^{2}\frac{(2.4(10)^{-8} C)(1.8(10)^{-6} C)}{(0.008 m)^{2}}$

$F_{E}=6.07 N$

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3 years ago

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2. by trying and solving

by not giving

by innovating

by being motivated

BY KNOWING THAT U CAN DO IT

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2 years ago