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2 years ago

Does the asteroid belt revolve around the sun?

1 answer:

3 0

These small rocky objects orbiting the sun have no atmosphere and are traces from the formation of the solar system. Thousands of asteroids can be found revolving around the sun in an “asteroid belt", an area located between the orbits of Mars and Jupiter.

brainliest please?

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The energy of atoms and molecules in an object due to their motion is_______ energy

QveST [7]

I think the answer is potential

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2 years ago

An egg is cracked/broken. Is this egg experiencing a Physical or Chemical change? (Hint: is it still an egg?)

Leokris [45]

The asnwer is the first choice! and lol yes its still luv ;)

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3 years ago

A scooter has wheels with a diameter of 120 mm. What is the angular speed of the wheels when the scooter is moving forward at 6.

nirvana33 [79]

To develop this problem we will apply the concepts related to angular kinematic movement, related to linear kinematic movement. Linear velocity can be described in terms of angular velocity as shown below,

$v = r\omega \rightarrow \omega = \frac{v}{r}$

Here,

v = Lineal velocity

$\omega$ = Angular velocity

r = Radius

Our values are

$v = 6/ms$

$r = \frac{d}{2} = \frac{120*10^{-3}}{2} = 0.06m$

Replacing to find the angular velocity we have,

$\omega = \frac{6m/s}{0.06m}$

$\omega = 100rad/s$

Convert the units to RPM we have that

$\omega = 100rad/s (\frac{1rev}{2\pi rad})(\frac{60s}{1m})$

$\omega = 955.41rpm$

Therefore the angular speed of the wheels when the scooter is moving forward at 6.00 m/s is 955.41rpm

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3 years ago

A ball is ejected to the right with an unknown horizontal velocity from the top of a pillar that is 50 meters in height. At the

dimulka [17.4K]

Answer:

15.67 m/s

Explanation:

The ball has a projectile motion, with a horizontal uniform motion with constant speed and a vertical accelerated motion with constant acceleration g=9.8 m/s^2 downward.

Let's consider the vertical motion only first: the vertical distance covered by the ball, which is S=50 m, is given by

$S=\frac{1}{2}gt^2$

where t is the time of the fall. Substituting S=50 m and re-arranging the equation, we can find t:

$t=\sqrt{\frac{2S}{g}}=\sqrt{\frac{2(50 m)}{9.8 m/s^2}}=3.19 s$

Now we now that the ball must cover a distance of 50 meters horizontally during this time, in order to fall inside the carriage; therefore, the velocity of the carriage should be:

$v=\frac{d}{t}=\frac{50 m}{3.19 s}=15.67 m/s$

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3 years ago

A piece of solar system debris that passes through Earth's atmosphere and strikes the ground is a/an _______.

Flauer [41]

The answer is meteorite. can i get brainliest?

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2 years ago