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pogonyaev
3 years ago
10

A track begins at 0 meters and has a total distance of 100 meters. Juliet starts at the 10-meter mark while practicing for a rac

e.
After running 45 meters, how far is she from the beginning of the track?


10 meters

35 meters

45 meters

55 meters
Physics
2 answers:
rosijanka [135]3 years ago
7 0
55 meters. If she started at 10 meters and ran 45 more, 10+45=55.
Rainbow [258]3 years ago
7 0

Answer:

the answer is (D) 55

Explanation:

i really don't have a explanation but i got it right on the test

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How are particles in liquids, solids, and gases the same? How are they different?
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Answer:

Gases, liquids and solids are all made up of atoms, molecules, and/or ions, but the behaviors of these particles differ in the three phases. ... gas are well separated with no regular arrangement. liquid are close together with no regular arrangement. solid are tightly packed, usually in a regular pattern.

Explanation:

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4 0
2 years ago
Which property best makes radio waves safe for diagnosing illnesses through magnetic resonance imaging?
aleksandrvk [35]

Answer:

It is used in MRI because it does not damage cells

Radio waves are used for space research because they have very long wavelengths

Explanation:

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4 0
3 years ago
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Nearly monochromatic light of wavelength 420 nm is split in two beams. The first beam traveled 105 nm to the screen more than th
leva [86]

Answer:

phase difference = π / 2

constructive interference

Explanation:

Given data

wavelength = 420 nm

1st beam = 105 nm

path difference = 105 nm

to find out

phase difference  and interference pattern of the two beams

solution

we use here equation of phase difference that is

phase difference = 2π / wavelength × Δx

put here value

phase difference = 2π / 420 × 105

phase difference = π / 2

and

we know that  here path difference Δx is the integral multiple of the wavelength  so it will be constructive interference

Δx is wavelength / 4

8 0
3 years ago
Rick shoots a basketball at an angle of 35' from the horizontal. It leaves his hands 7 feet from the ground with a velocity of 2
Korvikt [17]

Given:

The angle of projection of the basketball, θ=35°

The height at which the ball leaves the hand, h=7 ft

The initial velocity of the basketball, v=20 ft/s

To find:

The parametric equations describing the shot.

Explanation:

The range, x of the basketball is given by,

x=v\cos\theta t

On substituting the known values,

\begin{gathered} x=20\times\cos35\degree\times t \\ \implies x=16.4t \end{gathered}

The change in the height, y of the basketball is given by,

y=-v\sin\theta t+\frac{1}{2}gt^2

Where g is the acceleration due to gravity.

On substituting the known values,

\begin{gathered} y=-20\times\sin35\degree\times t+\frac{1}{2}\times32\times t^2 \\ \implies y=-11.5t+16t^2 \end{gathered}

Final answer:

The parametric equations describing the shot are

\begin{gathered} \begin{equation*} x=16.4t \end{equation*} \\ \begin{equation*} y=-11.5t+16t^2 \end{equation*} \end{gathered}

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