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makvit [3.9K]
3 years ago
12

Why do waves with high frequencies have short wavelengths

Physics
2 answers:
dalvyx [7]3 years ago
7 0

Answer: because  ν = velocity/λ where ν and λ are the frequency and wavelegth of the wave.

Explanation: In order to explain this problem we have to consider the relationship between frequency and wavelengths which  are related by the velocity of the wave as follows ν*λ=v where ν and λ are the frequency and wavelegth of the wave. These parameters have an inverse proportionality.

Then, ν = velocity/λ

makvit [3.9K]3 years ago
3 0

Answer:

The relationship between the wavelength and the frequency of a wave comes from the equation:

v = λ*f

Where v is the velocity of the wave, λ is the wavelength and f is the frequency.

So if we keep the velocity constant, you can see that if we decrease the wavelength, then the frequency must increase (to contrast the decrease in the other variable)

And the same in the other direction, if the wavelength increases, then the frequency must decrease.

So for a fixed velocity, as highest is the frequency, lower will be the wavelength.

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Two equal charges of magnitude 1.1 x 10 -7 C experience an electrostatic force of 4.2 x 10-4 N. How far apart are the centers of
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Answer:

0.51 m

Explanation:

From the question,

Applying coulomb's law,

F = kqq'/r²....................... Equation 1

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making r the subject of the equation

F×r² = kqq'

r² = kqq'/F

r = √(kqq'/F).................. Equation 2

Given: F = 4.2×10⁻⁴N, q = q' = 1.1×10⁻⁷C, k = 9×10⁹ Nm²/C²

Substitute these values into equation 2

r = √(9×10⁹×1.1×10⁻⁷×1.1×10⁻⁷/4.2×10⁻⁴)

r = √(1.1×1.1×9/4.2)(10⁹×10⁻⁷×10⁻⁷×10⁴)]

r = √(2.59×10⁻¹)

r = √(0.259)

r = 0.508

r ≈ 0.51 m

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Answer:

15s

Explanation:

Given parameters:

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Unknown:

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Solution:

To solve this problem, we make time the subject of the speed equation.

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We know that the (instantaneous) tangential velocity of such object is given by:

v=r.\omega

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