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makvit [3.9K]
2 years ago
12

Why do waves with high frequencies have short wavelengths

Physics
2 answers:
dalvyx [7]2 years ago
7 0

Answer: because  ν = velocity/λ where ν and λ are the frequency and wavelegth of the wave.

Explanation: In order to explain this problem we have to consider the relationship between frequency and wavelengths which  are related by the velocity of the wave as follows ν*λ=v where ν and λ are the frequency and wavelegth of the wave. These parameters have an inverse proportionality.

Then, ν = velocity/λ

makvit [3.9K]2 years ago
3 0

Answer:

The relationship between the wavelength and the frequency of a wave comes from the equation:

v = λ*f

Where v is the velocity of the wave, λ is the wavelength and f is the frequency.

So if we keep the velocity constant, you can see that if we decrease the wavelength, then the frequency must increase (to contrast the decrease in the other variable)

And the same in the other direction, if the wavelength increases, then the frequency must decrease.

So for a fixed velocity, as highest is the frequency, lower will be the wavelength.

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A solar flare is a sudden, rapid, and intense change in the brightness of the sun. Which of these is most
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electronic communications may be disrupted

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If these flares are directed towards Earth, they will interact with anything related to electricity and magnetism. Out of the given options third option is correct as the electronic communication will be disrupted. If the flares are strong a complete power blackout may occur and that would disrupt all the communication channel and power transmission. Such events have occurred in the past as well.

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Which statement places events during the Space Race in the correct order from the earliest to the most recent?
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En un experimento de calorimetría, 0.50 kg de un metal a 100°C se añaden a 0.50 kg de agua a 20°C en un vaso de calorímetro de a
Maru [420]

Answer:

c=0.14J/gC

Explanation:

A.

2) The specific heat will be the same because it is a property of the substance and does not depend on the medium.

B.

We can use the expression for heat transmission

Q=mc(T_2-T_1)

In this case the heat given by the metal (which is at a higher temperature) is equal to that gained by the water, that is to say

Q_1=-Q_2

for water we have to

c = 4.18J / g ° C

replacing we have

c_{metal}*(500g)(100\°C-25\°C)=-(250g)(4.18\frac{J}{g\°C})(20\°C-25\°C)\\c_{metal}=0.14\frac{J}{g\°C}

I hope this is useful for you

A.

2) El calor específico será igual porque es una propiedad de la sustancia y no depende del medio.

B.

Podemos usar la expresión para la transmisión de calor

Q=mc(T_2-T_1)

En este caso el calor cedido por el metal (que está a mayor temperatura) es igual al ganado por el agua, es decir

Q_1=-Q_2

para el agua tenemos que

c=4.18J/g°C

reemplazando tenemos

c_{metal}*(500g)(100\°C-25\°C)=-(250g)(4.18\frac{J}{g\°C})(20\°C-25\°C)\\c_{metal}=0.14\frac{J}{g\°C}

7 0
3 years ago
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