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Mekhanik [1.2K]
3 years ago
9

Which containe the most moles: water, aluminum, salt, baking soda

Chemistry
2 answers:
Zigmanuir [339]3 years ago
7 0
I’m going to assume that you were talking about the mass of one mole of each molecule/element. You do this by knowing the chemical formula and knowing the mass of the elements which can be found in a period table.
Water= H2O
H ≈ 1
O ≈16
Since there is two H multiply one by 2 and add 16 to it.
You get 18 so it’s 18g/mol

Aluminum is an element so you just have to go to the periodic table and look Al. You should get a number that is about 26.98.
So 26.98 g/mol is the answer

Salt=NaCl
Na ≈22.99
Cl ≈ 35.45
When you add those up you get 58.44 g/mol

Baking soda = NaHCO3
Na ≈22.99
H ≈1
C ≈12
O ≈16
Multiply 16 by 3 to get 48 and add everything together to get 83.99g/mol.
So if you had one mol of each the answer would be baking soda

If there are amount of miles that you forgot to add for the comparison, you just have to multiply.
For example
1 mol water is 18g/mol
.5mole water is 9g/mol
(.5*18 =9)
5 miles of water is 90g/mol
(5*18 = 90$
mariarad [96]3 years ago
4 0

Moles are the number of particles in a given weight. So unless you state the amount of water, aluminum, salt, and baking soda no one can not consider which contain the most moles.

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What are the advantages of using Fahrenheit ?
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You can better relate to the air temperature.

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Fahrenheit gives you almost double the precision of Celsius without having to use decimals.

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What’s the difference between chemical and nuclear energy?
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nuclear is explosive and has potential energy while the other has kinetic energy

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Do you think one mole of the different substances has the same amount?​
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It's because of Avagadro's number.

  • It is known as Avagadro's constant too.
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where

\\ \sf\longmapsto n=6.022\times 10^{23}

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2 years ago
If the pH of a 1.00-in. rainfall over 1800 miles2 is 3.70, how many kilograms of sulfuric acid, H2SO4, are present, assuming tha
NARA [144]
There are 2.32 x 10^6 kg sulfuric acid in the rainfall. 

Solution: 
We can find the volume of the solution by the product of 1.00 in and 1800 miles2: 
     1800 miles2 * 2.59e+6 sq m / 1 sq mi = 4.662 x 10^9 sq m 
     1.00 in * 1 m / 39.3701 in = 0.0254 m  
     Volume = 4.662 x 10^9 m^2 * 0.0254 m
                  = 1.184 x 10^8 m^3 * 1000 L / 1 m3
                  = 1.184 x 10^11 Liters 

We get the molarity of H2SO4 from the concentration of [H+] given by pH = 3.70: 
     [H+] = 10^-pH = 10^-3.7 = 0.000200 M 
     [H2SO4] = 0.000100 M  
 
By multiplying the molarity of sulfuric acid by the volume of the solution, we can get the number of moles of sulfuric acid: 
     1.184 x 10^11 L * 0.000100 mol/L H2SO4 = 2.36 x 10^7 moles H2SO4 

We can now calculate for the mass of sulfuric acid in the rainfall: 
     mass of H2SO4 = 2.36 x 10^7 moles * 98.079 g/mol
                               = 2.32 x 10^9 g * 1 kg / 1000 g
                               = 2.32 x 10^6 kg H2SO4
3 0
3 years ago
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In methane combustion, the following reaction pair is important: At 1500 K, the equilibrium constant Kp has a value of 0.003691
andre [41]

Explanation:

Let us assume that the value of K_{r} = 2.82 \times 10^{5} \times e^({\frac{-9835}{T}}) m^{6}/mol^{2}s

Also at 1500 K, K_{r} = 2.82 \times 10^{5} \times e^({\frac{-9835}{1500}}) m^{6}/mol^{2}s

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Relation between K_{p} and K_{c} is as follows.

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Putting the given values into the above formula as follows.

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         0.003691 = K_{c} \times 8.314 \times 1500

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Also,     K_{c} = \frac{K_{f}}{K_{r}}

or,                K_{f} = K_{c} \times K_{r}

                               = 2.9 \times 10^{-7} \times 400.613

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Thus, we can conclude that the value of K_{f} is 1.1617 \times 10^{-4} m^{6}/mol^{2}s.

6 0
3 years ago
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