1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
valentinak56 [21]
3 years ago
14

How many liters of 18.5 molar HCl stock solution will be needed to make 25.0 liters of 1.5 molar HCl solution? Show the work use

d to solve this problem.
Chemistry
1 answer:
Lera25 [3.4K]3 years ago
7 0
1) Find the number of moles that the final solution must contain

M = n / liters of solution => n = M*liters of solution

n = 1.5 mol/liter * 25.0 liter = 37.5 moles

2) Find how many liters of the stock solution contain 37.5 moles of HCL

M = n / liters of sulution => liters of solution = n / M = 37.5 mol / 18.5 mol/liter

liter of solution = 2.03 liter

Answer: 2.03 liter
You might be interested in
Whats does the elements Li (lithium),B (boron, and Ne neon) have in common?
nikdorinn [45]
They are in the same period (horizontal)
8 0
3 years ago
I’ll give brainlyiest (sorry if I spelled it wrong) to first correct answer
user100 [1]

Answer:

Dependent variable

Hope this helps :)

Have a great day !

5INGH

Brainliest please

Explanation:

8 0
3 years ago
What is the molarity (M) of .5 liter of a solution that has 205 g of NaCl dissolved in it?
jeka94

Answer:

<h2>Molarity = 7 mol / L</h2>

Explanation:

Since the mass of NaCl and it's volume has been given we can find the molarity by using the formula

<h3>C =  \frac{m}{M \times v}</h3>

where

C is the molarity

m is the mass

M is the molar mass

v is the volume

From the question

v = 0.5 L

m = 205 g

We must first find the molar mass and then substitute the values into the above formula

M( Na) = 23 , M( Cl) = 35.5

Molar mass of NaCl = 23 + 35.5 =

58.5 g/mol

So the molarity of NaCl is

C =  \frac{205}{0.5  \times 58.5}  \\ C =  \frac{205}{29.25}

C = 7.00854

We have the final answer as

<h3>Molarity = 7 mol / L</h3>

Hope this helps you

8 0
3 years ago
Who started the website "pintrest"
Mice21 [21]
Ben Silberman was the creator of Pinterest
8 0
2 years ago
Read 2 more answers
2.At 35°C, a small sample of methane gas (CH4) has a volume of 1.5 liters. The temperature of the methane gas is slowly cooled t
defon

Answer:

V₂ = 1.41 L

Explanation:

Given data:

Initial temperature = 35°C (35 +273.15 K = 308.15 K)

Initial volume = 1.5 L

Final temperature = 17°C (17+273.15 K = 290.15 K)

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 1.5 L × 290.15 K / 308.15 k

V₂ = 435.23 L.K / 308.15 k

V₂ = 1.41 L

5 0
3 years ago
Other questions:
  • Explain the meaning of each term in the symbol aXz
    12·1 answer
  • Propane, C3H8, consists of ________________ bonds and it can be expected to dissolve in hexane and to not dissolve in water.
    8·1 answer
  • 20 Which term is defined as a measure of the disorder of a system?
    14·2 answers
  • The idea that atoms are neither gained nor lost during a chemical reaction is called the law of
    8·1 answer
  • What bonds break? select that apply
    7·1 answer
  • Which of these is a physical property
    9·2 answers
  • Where do subduction zones occur
    6·1 answer
  • Determine the spec gravity of 500 mL alcohol if the density is 0.79g/ml
    8·1 answer
  • I am doing science, periodic table. what is an element that has 0 neutrons? I even searched online and it said that's not an ele
    13·1 answer
  • At 25◦C a 4 L sample of H2 exerts a pressure of 5 atm. What pressure would the same sample exert in a 2 L container at 25◦C?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!