How many liters of 18.5 molar HCl stock solution will be needed to make 25.0 liters of 1.5 molar HCl solution? Show the work use
d to solve this problem.
1 answer:
1) Find the number of moles that the final solution must contain
M = n / liters of solution => n = M*liters of solution
n = 1.5 mol/liter * 25.0 liter = 37.5 moles
2) Find how many liters of the stock solution contain 37.5 moles of HCL
M = n / liters of sulution => liters of solution = n / M = 37.5 mol / 18.5 mol/liter
liter of solution = 2.03 liter
Answer: 2.03 liter
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T = 20 % : 20 / 100 = 0.2
m1 = solute
m2 = Solvent
T = m1 / m1 + m2
0.2 = 500 g / 500 g + m2
0.2 * ( 500 + m2 ) = 500
0.2 * 500 + 0.2 m2 = 500
100 + 0.2 m2 = 500
0.2 m2 = 500 - 100
0.2 m2 = 400
m2 = 400 / 0.2
m2 = 2000 g of water
hope this helps!
