The student needs to dilute the stock to get the proper concentration. And during the dilution, the molar number of solute will not change. So the volume of stock needed is 2*0.1/1.75=0.114 L. Then dilute to 2.00 L.
The mass of hematite that contains 8.0×10³ kg of iron is 2.29 × 10⁴ kg.
<h3>What are iron ores?</h3>
Iron ores refers to minerals in which iron occur in combined form found in the earth's crust.
Some ores of iron include:
- hematite,
- magnetite,
- limonite, and
- siderite.
Molar mass of hematite, Fe₂O₃ = 160 g/mol
Molar mass iron = 56 g/mol
Percent mass of iron in hematite = 56/160 = 35%
The mass of hematite that contains 8.0×10³ kg of iron = 8.0 × 10³kg/0.35 = 2.29 × 10⁴ kg.
Therefore, the mass of hematite that contains 8.0×10³ kg of iron is 2.29 × 10⁴ kg.
Learn more about iron ores at: brainly.com/question/4693242
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Answer: so the answer would likely be
Explanation:
Answer:
98.8g (3 s.f.)
Explanation:
Use the mole = mass/mr equation to find the moles of CaO, then use the molar ratio to find the moles of Fe2O3, which is the same as CaO, (assuming the ratio is 1:1, as you haven't stated it clearly in the question). Then use the equation and input to find Mass, which is 98.8g to 3 s.f.
